Pumpkin Row
Platinum Member
- May 26, 2016
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So, I've been preparing for an important math test and a friend of mine(online) offered to help me with some graphing questions. I showed her my method, and she showed me hers, which is different. Mine feels a bit easier, but she says that hers is more "intuitive".
The points are -5, 2 and 3, -4
We both start off by subtracting the coordinates from each other to find the Slope
2-(-4) -6
-------=----
-5-3 8
Simplifying the answer: -3/4
The next step is where our methods differ. I'll start with mine;
I take an x and a y coordinate and place them into the equation y=mx+b(m=slope, b=y-intercept)
y=mx+b
2=-3/4*-5+b
I then solve for the y-intercept
2=-3/4*-5/1+b
2=15/4+b
2=15/4+-7/4
15/4+-7/4=8/4
8/4=2/1=2
So, now we have our equation; y=-3/4x-7/4
Now, my friend's method:
y-y1=m(x-x1)
4(y-2)=4(-3/4x - 15/4)
4y-8 = -3x -15
4y= -3x-7
y = -3/4x - 7/4
(Finding the Equation of a Line Given Two Points 2 | Coolmath.com she used the method shown here)
Does it matter as long as I get the right answer, and if her method is better, would it be worth swapping methods 39 hours before my test or would that be a hindrance?
The points are -5, 2 and 3, -4
We both start off by subtracting the coordinates from each other to find the Slope
2-(-4) -6
-------=----
-5-3 8
Simplifying the answer: -3/4
The next step is where our methods differ. I'll start with mine;
I take an x and a y coordinate and place them into the equation y=mx+b(m=slope, b=y-intercept)
y=mx+b
2=-3/4*-5+b
I then solve for the y-intercept
2=-3/4*-5/1+b
2=15/4+b
2=15/4+-7/4
15/4+-7/4=8/4
8/4=2/1=2
So, now we have our equation; y=-3/4x-7/4
Now, my friend's method:
y-y1=m(x-x1)
4(y-2)=4(-3/4x - 15/4)
4y-8 = -3x -15
4y= -3x-7
y = -3/4x - 7/4
(Finding the Equation of a Line Given Two Points 2 | Coolmath.com she used the method shown here)
Does it matter as long as I get the right answer, and if her method is better, would it be worth swapping methods 39 hours before my test or would that be a hindrance?