Who's pushing solar cars?
The question isn't how much material it will take to build 10,000 square miles of solar panel. The question is how much material will that panel have used by the time it's worn out - let's say, in 25 years.
Let's say the panel contains one pound of steel per square meter. That's being generous. The photovoltaic material is lain on by vapor deposition and is microns thick, but let's be very generous and say we need an ounce per square meter. Glass cover will weigh 5 kg (
Glass Weight Calculator - Glass Technology Services Ltd (GTS)) per square meter. So, for the entire assembly, we will need
10,000 square miles = 25,900,000,000 sq m -> 25,900,000,000 pounds of steel, 1,618,750,000 pounds of germanium and 284,900,000,000 pounds of glazing
At an efficiency of 20%, that 10,000 sq mi panel would produce about
10,000 sq mi x 5280 x5280 x 12 x 12 = 40,144,896,000,000
divide by 3003 sq in. in a std panel = 13,368,263,736 panels.
Times 225W power from a standard panel = 3,007,859,340,659 equals roughly 3 TW.
Let's produce one terrawatt each from coal, natural gas and petroleum.
One TW would require 952.4 million pounds of coal per hour
One TW would require 101 billion cu feet of natural gas per hour
One TW would require 70 million gallons of petroleum per hour.
In 25 years we would need to burn more than
208.575 trillion pounds of coal
22.12 quadrillion cubic feet of natural gas
15.33 trillion gallons of petroleum
Get it?