All objects emit in accordance to their temperatures, all the time.
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No they don't...they only emit in accordance to their temperatures if they are in a vacuum...I provided emails from several top shelf physicists who stated exactly that. The fact that you prefer to believe in your misunderstanding says volumes... If objects emitted in accordance to their temperatures all the time, there would only be a need for one version of the SB law since nothing would change if the object were in the presence of other objects...
You didn't ask those physicists if the temperature of the radiation bath stopped or slowed the internal production of radiation in the object. You didnt ask whether the change in energy for the object was the net result of output minus input.
Why don't you put up all of the replies? Not just the ambiguous one you showed us?
I asked if
applied only to theoretical perfect black bodies radiating into theoretical empty vacuum because you were making the claim that the equation applied equally to everything...and you were wrong...that equation applies only to a perfect radiator all alone in a perfect vacuum...
Since I am perfectly capable of reading an equation, there was no need to ask what
says...it is written right there ...the radiation being emitted by a radiator, that is not a perfect black body and that is not in an empty vacuum equal to its emissivity times the SB constant times its area times the difference to the 4th power of its own temperarue and the temperature of its surroundings. It is a straight forward equation , easily read and completely unambiguous...