Hillary was awarded 3 delegates by coin toss!

[theDoctorisIn]

There's no question that it's a little goofy that anything like this is determined by coin flip. But it doesn't actually mean anything - the flips were for the state convention, not the actual convention, and in the end Hillary and Sanders will almost certainly split Iowa's 44 delegates right down the middle.

What are the odds of winning 6 out of 6?

I'll bet the old crook is sad she didn't play the Powerball a couple of weeks back, her odds of winning that were better.

1/64. Not that far odds - about the same as getting three-of-a-kind in a game of 5-card stud.

 

[Uncensored2008]

which has to do with a coin flip how?

The odds of winning 6 consecutive coin tosses is about 1 in 30 billion.

But a career criminal like Hillary would never cheat, so we'll just say her luck is unprecedented.

 

[flacaltenn]

There's no question that it's a little goofy that anything like this is determined by coin flip. But it doesn't actually mean anything - the flips were for the state convention, not the actual convention, and in the end Hillary and Sanders will almost certainly split Iowa's 44 delegates right down the middle.

Just wait til you see the Dem rules for the State Convention.. I hear it involves a "dunk tank" and selling tickets..

 

[theDoctorisIn]

which has to do with a coin flip how?

The odds of winning 6 consecutive coin tosses is about 1 in 30 billion.

But a career criminal like Hillary would never cheat, so we'll just say her luck is unprecedented.

I think you might want to check your math there, cowboy.

 

[Siete]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

 

[Valerie]

Clinton's Iowa victory means she will collect 23 delegates and Sen. Bernie Sanders will win 21.

With her advantage in superdelegates Clinton now has a total of 385 delegates. Sanders has 29.

It takes 2,382 delegates to win the Democratic nomination for president.

Clinton takes Iowa, beating back Sanders' strong challenge

 

[Uncensored2008]

1/64. Not that far odds - about the same as getting three-of-a-kind in a game of 5-card stud.

BWAHAHAHAHAHAHAHAH

Yeah sparky, you go with that.

2^6 is not the statistical probability across 6 coin tosses.

{
What actually happens is that when we examine the possibility of an unsuccessful run of heads at toss i, we slightly bias the outcome at toss i+1. A demonstration will show exactly how this happens.

For the sample problem of a sequence of two heads out of four tosses, we can first examine the chance of a negative outcome starting at toss 1. There are just four possible outcomes that have two tosses starting at position 1: HH HT TH TT And only one of these tosses yielded two heads in a row, so the probability of not seeing two heads after two tosses is 3/4.

But now when we look at the sequence of tosses starting at position two, we have to throw out the outcomes where we had two heads at toss one - we've already seen two heads, so we can't continue flipping coins in those outcomes. So our universe of possible outcomes is now a bit different: HTH HTT THH THT TTH TTT Instead of eight outcomes, we have six. And if we look at the first toss seen in position two, instead of having an even distribution of heads and tails, you can see that sample is biased: only two have a head in position two, while four have tails. So the chances of not seeing two heads starting at position two increases to 5/6. Note that this change in probability occurs because we have selected only those outcomes without a streak of two heads at position one.

Likewise, when we look at the possible outcomes for streaks starting at position three, we get a different probability again. Because we have to throw out one sequence in the previous test, the universe of possible outcomes is now limited to: HTHH HTHT HTTH HTTT THTH THTT TTHH TTHT TTTH TTTT So now we have just ten possible outcomes, and two of those will produce the desired outcome, meaning the probability has changed to 4/5.

So what is the probability of all three possible positions not containing a streak? That would be (3/4)*(5/6)*(4/5) which reduces nicely to 1/2, the correct answer.}
20 Heads In a Row - What Are the Odds?

Factor in the streak and it is actually 2^6^6 or 64^6

 

[Remodeling Maidiac]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

One 30 second video from one caucus site. Tails was called by "someone" and it came up heads. Only 5 more videos to go!

 

[Valerie]

well looky who's a math whiz

 

[SwimExpert]

No I mean to allege that the DNC wanted to make sure Hillary could claim victory.

The DNC? You mean, the same DNC that is chaired by Wasserman-Shultz? The same Wasserman-Shultz who is best friends with Obama? The same Obama who has come to hate Clinton so much they tried to pressure Joe Biden into running so that he could put her to bed?

That DNC?

 

[Valerie]

BWAHAHAHAHAHAHAHAH

Yeah sparky, you go with that.

2^6 is not the statistical probability across 6 coin tosses.

{
What actually happens is that when we examine the possibility of an unsuccessful run of heads at toss i, we slightly bias the outcome at toss i+1. A demonstration will show exactly how this happens.

For the sample problem of a sequence of two heads out of four tosses, we can first examine the chance of a negative outcome starting at toss 1. There are just four possible outcomes that have two tosses starting at position 1: HH HT TH TT And only one of these tosses yielded two heads in a row, so the probability of not seeing two heads after two tosses is 3/4.

But now when we look at the sequence of tosses starting at position two, we have to throw out the outcomes where we had two heads at toss one - we've already seen two heads, so we can't continue flipping coins in those outcomes. So our universe of possible outcomes is now a bit different: HTH HTT THH THT TTH TTT Instead of eight outcomes, we have six. And if we look at the first toss seen in position two, instead of having an even distribution of heads and tails, you can see that sample is biased: only two have a head in position two, while four have tails. So the chances of not seeing two heads starting at position two increases to 5/6. Note that this change in probability occurs because we have selected only those outcomes without a streak of two heads at position one.

Likewise, when we look at the possible outcomes for streaks starting at position three, we get a different probability again. Because we have to throw out one sequence in the previous test, the universe of possible outcomes is now limited to: HTHH HTHT HTTH HTTT THTH THTT TTHH TTHT TTTH TTTT So now we have just ten possible outcomes, and two of those will produce the desired outcome, meaning the probability has changed to 4/5.

So what is the probability of all three possible positions not containing a streak? That would be (3/4)*(5/6)*(4/5) which reduces nicely to 1/2, the correct answer.}
20 Heads In a Row - What Are the Odds?

Factor in the streak and it is actually 2^6^6 or 64^6

bwahaha indeed

 

[theDoctorisIn]

1/64. Not that far odds - about the same as getting three-of-a-kind in a game of 5-card stud.

BWAHAHAHAHAHAHAHAH

Yeah sparky, you go with that.

2^6 is not the statistical probability across 6 coin tosses.

{
What actually happens is that when we examine the possibility of an unsuccessful run of heads at toss i, we slightly bias the outcome at toss i+1. A demonstration will show exactly how this happens.

For the sample problem of a sequence of two heads out of four tosses, we can first examine the chance of a negative outcome starting at toss 1. There are just four possible outcomes that have two tosses starting at position 1: HH HT TH TT And only one of these tosses yielded two heads in a row, so the probability of not seeing two heads after two tosses is 3/4.

But now when we look at the sequence of tosses starting at position two, we have to throw out the outcomes where we had two heads at toss one - we've already seen two heads, so we can't continue flipping coins in those outcomes. So our universe of possible outcomes is now a bit different: HTH HTT THH THT TTH TTT Instead of eight outcomes, we have six. And if we look at the first toss seen in position two, instead of having an even distribution of heads and tails, you can see that sample is biased: only two have a head in position two, while four have tails. So the chances of not seeing two heads starting at position two increases to 5/6. Note that this change in probability occurs because we have selected only those outcomes without a streak of two heads at position one.

Likewise, when we look at the possible outcomes for streaks starting at position three, we get a different probability again. Because we have to throw out one sequence in the previous test, the universe of possible outcomes is now limited to: HTHH HTHT HTTH HTTT THTH THTT TTHH TTHT TTTH TTTT So now we have just ten possible outcomes, and two of those will produce the desired outcome, meaning the probability has changed to 4/5.

So what is the probability of all three possible positions not containing a streak? That would be (3/4)*(5/6)*(4/5) which reduces nicely to 1/2, the correct answer.}
20 Heads In a Row - What Are the Odds?

Factor in the streak and it is actually 2^6^6 or 64^6

There was no "streak" - Hillary's campaign won 6 different coin tosses in 6 different places. There's no reason to believe that all of those coins landed on the same face, either.

 

[BlueGin]

Now they are reporting that the DNC did not staff 90 pricincts

They also said on the news that they ran out of ballots and registration forms. Even though they allegedly expected record turn out.

 

[flacaltenn]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

Sure sure sure.. EXCEPT that process for ADDING those "toss-up" delegates is based on ACTUAL ATTENDANCE and votes cast.. And THAT information is strangely "secret"... Isn't it???

 

[Ravi]

1/64. Not that far odds - about the same as getting three-of-a-kind in a game of 5-card stud.

BWAHAHAHAHAHAHAHAH

Yeah sparky, you go with that.

2^6 is not the statistical probability across 6 coin tosses.

{
What actually happens is that when we examine the possibility of an unsuccessful run of heads at toss i, we slightly bias the outcome at toss i+1. A demonstration will show exactly how this happens.

For the sample problem of a sequence of two heads out of four tosses, we can first examine the chance of a negative outcome starting at toss 1. There are just four possible outcomes that have two tosses starting at position 1: HH HT TH TT And only one of these tosses yielded two heads in a row, so the probability of not seeing two heads after two tosses is 3/4.

But now when we look at the sequence of tosses starting at position two, we have to throw out the outcomes where we had two heads at toss one - we've already seen two heads, so we can't continue flipping coins in those outcomes. So our universe of possible outcomes is now a bit different: HTH HTT THH THT TTH TTT Instead of eight outcomes, we have six. And if we look at the first toss seen in position two, instead of having an even distribution of heads and tails, you can see that sample is biased: only two have a head in position two, while four have tails. So the chances of not seeing two heads starting at position two increases to 5/6. Note that this change in probability occurs because we have selected only those outcomes without a streak of two heads at position one.

Likewise, when we look at the possible outcomes for streaks starting at position three, we get a different probability again. Because we have to throw out one sequence in the previous test, the universe of possible outcomes is now limited to: HTHH HTHT HTTH HTTT THTH THTT TTHH TTHT TTTH TTTT So now we have just ten possible outcomes, and two of those will produce the desired outcome, meaning the probability has changed to 4/5.

So what is the probability of all three possible positions not containing a streak? That would be (3/4)*(5/6)*(4/5) which reduces nicely to 1/2, the correct answer.}
20 Heads In a Row - What Are the Odds?

Factor in the streak and it is actually 2^6^6 or 64^6

There was no "streak" - Hillary's campaign won 6 different coin tosses in 6 different places. There's no reason to believe that all of those coins landed on the same face, either.

hahahahaha! Your post reminded me of the scene where Indiana Jones just shot the guy that was threatening a sword fight. Poor Eunich2008.

 

[Remodeling Maidiac]

No I mean to allege that the DNC wanted to make sure Hillary could claim victory.

The DNC? You mean, the same DNC that is chaired by Wasserman-Shultz? The same Wasserman-Shultz who is best friends with Obama? The same Obama who has come to hate Clinton so much they tried to pressure Joe Biden into running so that he could put her to bed?

That DNC?

Yes.


By the way do you have any spare tinfoil?

 

[Siete]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

Sure sure sure.. EXCEPT that process for ADDING those "toss-up" delegates is based on ACTUAL ATTENDANCE and votes cast.. And THAT information is strangely "secret"... Isn't it???

apparently there was enough different people at the polling places to make sure everything was above board ... not one single person said otherwise either.

6 different counties,
6 different coins
keeping x amount of people on the same page, telling the same story ?



if you or anyone else believes that, hide a tooth under your pillow tonight.

 

[flacaltenn]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

Sure sure sure.. EXCEPT that process for ADDING those "toss-up" delegates is based on ACTUAL ATTENDANCE and votes cast.. And THAT information is strangely "secret"... Isn't it???

apparently there was enough different people at the polling places to make sure everything was above board ... not one single person said otherwise either.

6 different counties,
6 different coins
keeping x amount of people on the same page, telling the same story ?



if you or anyone else believes that, hide a tooth under your pillow tonight.

Isn't that "voter disenfranchisement" ??? Was it because it was an ODD number of delegates in that precinct and no one could do the math on the ACTUAL VOTE COUNT?

So having an ODD number of delegates in a precinct necessitates a game of chance?
Why aren't you curious about this???

 

[Remodeling Maidiac]

officials in different counties flipped the coins .. Democratic rules.

Coin tosses used to determine county delegates in Clinton-Sanders race



video and all ...

Sure sure sure.. EXCEPT that process for ADDING those "toss-up" delegates is based on ACTUAL ATTENDANCE and votes cast.. And THAT information is strangely "secret"... Isn't it???

apparently there was enough different people at the polling places to make sure everything was above board ... not one single person said otherwise either.

6 different counties,
6 different coins
keeping x amount of people on the same page, telling the same story ?



if you or anyone else believes that, hide a tooth under your pillow tonight.

The video you offered did not show what you described just now.

It showed a handful of people listening to some fat lady as she tossed a coin & declared Hillary the winner. She then walked over to the Sanders group to inform them of what she did and who got the delegate as a result.

 

[Uncensored2008]

hahahahaha! Your post reminded me of the scene where Indiana Jones just shot the guy that was threatening a sword fight. Poor Eunich2008.

Poor Rati - math is hard...