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But that's specious.
That Thunderball stat site is just rude, IMO. Just trying to suck people into losing more money. They are generating noisy data from too-small a sample size to try to fool people into believing one number may have an advantage over the other, causing them to falsely inflate their expectation.
There are 39 Thunderballs, 5 balls drawn = 69 million+ combinations. How many historical drawings? 5,000? 10,000 maaaaybe?
Those noisy charts will trend to even frequencies for each number, over time.
1,2...7 has no less chance than any other 7-digit number.
"Before I lay the two cards down, I shuffle them behind my back."
Sorry for the confusion, if any.
Good point. I’ll agree that a string of consecutive numbers obviously has less chance than a string of non-consecutive ones.
But I maintain (or I think I do) that the numbers I said have just as much chance as any other *single* combination of numbers.
Times like this I wish I had taken some math courses beyond high school. Hated math with a passion, but I think I’d dig stuff like this.
Meaning, your point is correct, if you consider them re-ordered, because it is a rule that the left card is always flipped.Whatever reason it was put there, it made the odds 50/50.
A randomly generated 7-digit number is just that, though. Random.Again, I think it depends on how you look at it.
BUT, you do have a semantic point. That's the semantic debate: whether or not the cards are then "re-ordered", left to right.
Meaning, your point is correct, if you consider them re-ordered, because it is a rule that the left card is always flipped.
Probably better to leave out that the card on the left is flipped, and just say I flip over a card.
But you agree that, if you collected pairs of draws from an infinite deck, what you would eventually have is:How is there ever four permutations? There’s two black cards, two red, or one of each.
A randomly generated 7-digit number is just that, though. Random.
Yes, true.Assuming it is random.
Ok, I’m too tired to think about it anymore tonight, but at least it got my brain workingBut you agree that, if you collected pairs of draws from an infinite deck, what you would eventually have is:
25% both black
50% one black, one red
25% both red
Right?
I guess there’s infinitesimal differences in real life lotto drawings like some being slightly different shapes or weights, or being put into the machines in a certain order that might slightly give certain numbered balls a greater chance.Assuming it is random. Assuming that everything is pure. Is it pure?
I guess there’s infinitesimal differences in real life lotto drawings like some being slightly different shapes or weights, or being put into the machines in a certain order that might slightly give certain numbered balls a greater chance.
But, in a pure environment, I’d have to assume any combination of numbers has just as much chance as any other combination of numbers.
In fact, there’s just as much chance this weeks numbers will be the same as last weeks numbers as there is it will be any other single combination. Right?
One might contend that is a distinction without a difference.They are the same combination.
They are distinct permutations.
I see what you're saying, but that really only works in a finite deck of cards. Removing one red card still leaves an equal amount of red and black cards in the infinite deck, meaning the odds are still 50/50.Because, in and of itself, each individual card draw will always have a 50/50 chance, but the chance that *two* consecutive draws will be the same color lowers the probability. Am I right?
But there's a 50/50 chance that they will match. If you already know what the first coin flip reveals, the odds are 50/50 that the second will match.Hmmm, but if you flip a coin twice there’s a 1/4 chance both flips will be heads.
So, in scenarios 3 and 4, if a flip a card, and it is red, you can only eliminate 1 permutation. Three remain:
BR
RB
RR