If I remember right Eots mentioned that the beams near the base of the towers had to be about 4 inches thick.... That's an awful lot of thermite to burn through that much steel without anyone noticing....
Thermite in general makes an ugly hole with molten metal drips/blobs. It doesn't make clean cuts. It's a powder that undergoes a violent chemical reaction as seen in the video below.
Thermite VS Car Cool Video
Note how much thermite is used. The pot is about a liter, but how much thermite is that?
Stoichiometric thermite requires 2 moles of Al per 1 mole of Fe2O3
2Al + Fe2O3 = Al2O3 + 2Fe
2 moles of Al weigh 54 g
1 mole of Fe2O3 weighs 160 g
density of Al=2.64 g/cc
density of Fe2O3=5.24 g/cc
54 grams of Al is equivalent to 20.5 cc of Al.
160g of Fe2O3 is equivalent to 30.5 cc of Fe2O3
Therefore, 51 cc of fully dense powder of 20.5 cc Al and 30.5 cc Fe2O3 weighs (54+160) g = 214 g.
A volume of 1000 cc would weigh (1000/51)*214 = 4.2 kg
For a powder packing density of 50%, the powder would weigh:
0.5*4.2 kg = 2.1 kg = 4.8 lb
That much just to burn a small hole in a small car engine. I bet it's even an aluminum block but lets say it isn't. How much do you think it would take to burn a massive core column? Then add enough to burn for 6 weeks! You see where we're going. You'd need tons.
Here's a Debunking911 Fun Fact!
How much mass would be required to produce molten iron from thermite equal to the same volume of molten aluminum droplets shown flowing from the south tower window:
A mole of Fe weighs 54 g. For every mole of Fe produced by thermite, one mole of Al and 0.5 mole of Fe2O3 is needed.
2Al + Fe2O3 = Al2O3 + 2Fe
One mole of Al weighs 27 g. 0.5 mole of Fe2O3 weighs 80 g.
Therefore, (27 + 80) g = 107 g of Al and Fe2O3 is needed to produce 54 g of Fe.
That means the mass of the reactants to that of Fe produced is a ratio of 107/54 = 2. The mass of thermite reactants (Al, Fe2O3) is twice that of the molten iron produced.
Comparing the weight of molten aluminum droplets compared with iron:
Iron is 7.9 g/cc. Aluminum is 2.64 g/cc. Fe is denser than Al by a factor of 3. For the same volume of droplets, Fe would have three times the mass as Al.
To produce the iron from thermite requires a reactant mass that is a factor of 2 more than the iron produced. Also, Fe is 3 times as dense as Al. So, it would take 2*3 = 6 times as much mass to produce the same volume of molten iron droplets from thermite compared with molten aluminum droplets.
Example:
Assume 3000 lbs of aluminum fell from the towers. If it had been molten iron produced by thermite, then 6*3000 = 18,000 lbs of thermite reactants would have been required to produce that same volume of falling mass.
Suppose 10 tons of molten aluminum fell from the south tower, about 1/8th of that available from the airplane. If it had been molten iron produced from thermite, 60 tons of thermite reactants would have to have been stored in Fuji Bank to produce the same volume spilling out of the south tower. The section of floor would have to hold all of that plus the aircraft.
*Amount of aluminum can be ascertained by counting the droplets and measuring their size compared to the known size of the window. It's not easy to get a good number on this. It's based on the number of slugs seen in video stills, their size relative to the window width which was about 22 inches, and the density of aluminum, assuming this was aluminum.
Density of metals
The weight of a gallon of aluminum is about 22.5 pounds. A hundred of these would already be 2250 lbs. A gallon size is not unlike the size of the slugs that were pouring out the window. Look at them relative to the window size. They look small at first, but when you realize how big the towers were, the slugs were fairly large. It must have been in the thousands of pounds.
Thermite and Sulfur- Debunking 9/11 Conspiracy Theories and Controlled Demolition