Dagosa
Gold Member
- Oct 22, 2012
- 22,594
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- #161
You have no problem looking foolish making up math problems then omitting 1/2 the necessary values needed to solve it. By your own admissions and corrections, you miss spelled “the nature“ of the equation and failed to give enough values to solve it. Ha ha. Take a dementia test Trump. I had to correct you zercons twice.....I had no problem using it. Other than needing the conversion factor for w/m^2 to deg C, there's missing. You're an idiot.Oh, so you conveniently omitted a pair of necessary values to do what, have me check your spelling again.415 is the current concentration. So you can input 300 ppm as the inital and 415 as the final to see what the change was. Or you can input 415 as the initial and say 580 as the final to see what the change will be.Ah, yes. But all you’ll get is an expressionBet your asteroid I do.∆T = 5.35 k ln (CO2F/CO2I) where ∆T = change in temperature, k = climate sensitivity, CO2F = final carbon dioxide concentration, CO2I = initial carbon dioxide concentration ...
Are you familiar with the behavior of logrithmic functions?
I know MORE about logarithmic functions then you, guaranteed ...you misspelled LOGARITHMIC.
Then can you solve for k @ 415 ppm? ...
That’s a silly question. You still have two other unknowns and you didn’t say if 415 ppm was the initial or final concentration of CO2.
At least if you’re going to pretend to know math, pretend with more Information ....faker.
But be careful about your units because that equation does not give the answer in deg C.
Another mistake on your part. You need both pairs of values to make two natural log equations because you still have two unknowns, delta t and the constant K. So far, you’re 0-3 in making yourself look smart.
Fly away pigeons.