I did .. Go to the questions I posed in the post link above. I'd love to hear how YOUR theory handles those explanations..
WHY? your questions do not in any way negate or disprove my statements...
But here ya go... Your questions..
"Just bought another Lab grade IR thermometer.. (needed one with smaller field of view for small electronic components).. I bring the sensor to room temperature.. Point it at leak in the window sill.. You telling me that I can't READ 12degF below room temp because the "photons aren't gonna travel from a cooler to warmer object"???? "-flac...
Are you reading the flow from warmer to colder? Seriously is that what your thermometer is reading? Or is it the change in temperature itself. OR in this example from wikkipedia...
Obviously in my example,, I'm reading a COLDER object.. It's a leaking window 15degF BELOW ambient...
Infrared thermometer - Wikipedia, the free encyclopedia
According to wikki they can be used for various purposes but somehow proving back-radiation isn't one of them... Hmmm...
Sorry you've apparently never used one of these.. They are carried by every HVAC tech on the planet.. I've got 3 or 4 in my lab.. No mystery.. They will read HOTTER or COLDER than the ambient surroundings.. Here...
Don't care about confusing heat with other sources if the target is isolated in the field of view. Temp is temp at an IC on a circuit board. Or a chilly window leak...
Simple dude show me the text book which states it being a fact and we are done.. Shouldn't be too hard if it's as factual and obvious as you claim...
If photon energy WAS NOT flowing from colder to warmer AND bring thermal energy to the IR sensor in those instruments, that IR thermometer WOULD NOT FUNCTION for below ambient targets -- would it?
There's your "backradiation" from a cooler sky thru radiative heating..
Your next question...
"2) I place 2 identical metal bars on strings in a vacuum container with a uniform constant heat source outside. They come to equilibrium temp at 100DegF... Does that mean they don't radiate EM IR photons anymore at each other.. ((And indeed uniformly out in all directions?)) So if I point my IR reader at them --- they somehow are not radiating black bodies anymore? Or is the distribution of their radiation limited to an inate guidance system that measures the temperature of EVERY OBJECT in their path?"
Sure they may radiate at one another, BUT... And please pay attention this time because you keep ignoring this point.... DO THEY EFFECT CHANGE IN THEIR HEAT SOURCE? OR ONE ANOTHER?
NO!
Wasn't my question. Did not ask if they effected ANY change in Temp.. I asked if they STOPPED radiating at each other? Because by YOUR rules, there is no thermal gradient and therefore no heat flow.. So --- can you answer the question now???
And why? Because the nature of blackbody radiation, or thermal equilibrium achieved by both bodies negating any gain in temperature from one another..
But hey, Don't take my word for it...
https://en.wikipedia.org/wiki/Black-body_radiation
Two bodies that are at the same temperature stay in thermal equilibrium, so a body at temperature T surrounded by a cloud of light at temperature T on average will emit as much light into the cloud as it absorbs, following Prevost's exchange principle, which refers to radiative equilibrium. The principle of detailed balance says that in thermodynamic equilibrium every elementary process works equally in its forward and backward sense.[20][21] Prevost also showed that the emission from a body is logically determined solely by its own internal state. The causal effect of thermodynamic absorption on thermodynamic (spontaneous) emission is not direct, but is only indirect as it affects the internal state of the body. This means that at thermodynamic equilibrium the amount of every wavelength in every direction of thermal radiation emitted by a body at temperature T, black or not, is equal to the corresponding amount that the body absorbs because it is surrounded by light at temperature T.[22]
You are circle-talking, pretending that because something can radiate towards it's source, that means it can effect change in that source. It's a false assumption. Mathematically it should, but due to QM or Quantum theory being incomplete (the math behind it), reality and real world experience shows it doesn't effect change in the source.. See the problem yet?
You like Ian and so many others learned to do the math through a process, but you didn't learn to question it or think through what it means in application. Hence your attempt to use an IR thermometer to prove backradiation. If it were really that simple, there wouldn't be a case against it would there... It would be in the text books wouldn't it.. Well it's not and the reason is it's a mathematical concept which doesn't stand up to real world observation..
NOW can you please explain how it is you think that because an object can radiate in any and all directions at once, that it automatically means it can and will effect change in its greater source???
Please, if you can't answer it fine, just don't ignore it and try to make up my position for me... It's getting old..
BTW.. "kinda wins in the long run." LOL are you serious.. It wins but you aren't gonna admit it so you try and justify it with that ? ROFL