Your attempt at describing the mechanism of energy movement was that of a petulant child...rather than simply acknowledge that we don't know, you come up with some half assed description of energy movement...and nothing to do with the actual mechanism...pointing out your error is what adults do with petulant children so that they don't grow up believing that they know things that they don't. Guess your parents dropped the ball with you.
You are still stalling. You still haven't given me a reason why you think this is wrong:
The atoms at and near the surface are vibrating with a wide spectrum of wavelengths (see Plank's radiation law.) When charges vibrate, they must radiate energy. There is nothing outside that body that can stop atoms from vibrating. There is nothing outside that body that can stop the vibrating atoms from radiating EM energy.
You have two molecules one at 10K and one at 236K.
These molecules are in a vacuum and in close proximity to one another..
Each one emits photons relative to their temperature towards the cold of space at 2K.
The photons from the molecule at 236K are moderately energetic and in a very short wave 16-22um
The photons from the other molecule at 10K are extremely low in energy and are in a 10 meter wave length. very low energy.
As gasses go, the photon can only be absorbed by another gas at roughly its same frequency. The colder photon will pass through warmer molecule giving it no effect as will the warmer pass through the colder because they are grey bodies. Without absorption and molecular collisions neither gas will warm.
As solids go (black bodies), both will again radiate in wavelengths and excitement relative to their temperatures. The cooler molecule will throw out 1 photon to the warmer molecules 2,000 (temperature/excitement level). These photons will have very little power from the cooler molecule and 2,000 times more power in each from the warmer molecule. (wave propagation theory)
A cooler object can not warm a warmer object by simple observation of the theoretical process.
A colder objects emitted energy is unable to influence the warmer molecule simply because the output and excitement of the outgoing photons can not overcome the warmer objects output. This is why "reflection" in fiber optics might be important.
Again, this is all theoretical. No observations of WHY have been documented. But this is a thing that most radio, fiber-optic and microwave engineering people know and deal with every day. They observe the problems and deal with them.. And sometimes the fix makes absolutely no sense at all..