If the Space Station could spin on a central axis how much speed would it need to create gravity?

If spun, all the solar panels and extraneous bits would have to be built to endure the force.
 
Depends on the radius. The 2001 station would have needed just 0.5 - 1 RPM
Think about that.

The diameter of the a space station turning one full revolution per minute. If the diameter of the station is 500 meters......
 
How to Calculate the Force of Gravity on the Earth’s Surface - dummies

You can use Newton’s law of gravitation to get the acceleration due to gravity, g, on the surface of the Earth just by knowing the gravitational constant G, the radius of the Earth, and the mass of the Earth. The force on an object of mass m1 near the surface of the Earth is

F = m1g

This force is provided by gravity between the object and the Earth, according to Newton’s gravity formula, and so you can write

331266.image1.png
<img src="https://www.dummies.com/wp-content/uploads/331266.image1.png" width="97" height="49" alt="image1.png"/>

The radius of the Earth, re, is about 6.38 × 106 meters, and the mass of the Earth is 5.98 × 1024 kilograms. Putting in the numbers, you have

331267.image2.png
<img src="https://www.dummies.com/wp-content/uploads/331267.image2.png" width="329" height="73" alt="image2.png"/>

Dividing both sides by m1 gives you the acceleration due to gravity:

331268.image3.png
<img src="https://www.dummies.com/wp-content/uploads/331268.image3.png" width="293" height="117" alt="image3.png"/>

Newton’s law of gravitation gives you the acceleration due to gravity near the surface of the Earth: 9.8 meters/second2.

Of course, you can measure g by letting an apple drop and timing it, but what fun is that when you can calculate it in a roundabout way that requires you to first measure the mass of the Earth?
I'm not sure this applies. We're talking centrifugal force as opposed to gravity.
 
Simulating Gravity in Space

In order for the astronaut to move in a circle with the space station, there must be a centripetal (center-pointing) force on the astronaut. The outside wall of the space station can supply this force. Notice that this centripetal force mimics the support force exerted by the floor on a person on Earth. Therefore, this centripetal force will make the astronaut feel heavy! There is no gravitational force - just a support force - so the astronaut isn't really heavier, she just feels heavier. All we need to do is adjust the rotational speed of the space station so that the centripetal force applied to the astronaut by the space station equals the astronaut's weight on Earth, mg, and she will feel her normal weight (but not be her normal weight!).
 
If spun, all the solar panels and extraneous bits would have to be built to endure the force.
But what force? There is no resistance in space right? No atmosphere or air so what force would apply against the panels?
And even if true the panels could be placed on a non rotating section right?
 
They would need to be magnetized.
Why? Isn't the point of false gravity to simulate light gravity and bypass the need for external measures?

I don't think the space station is designed for the perimeter to be used as a floor. That might be something to consider if another is built.
No doubt it isn't. I just don't get why. Cost? Technical restraints? Risk?
I think that there is an enormous cost to countering the gyroscopic effect of a spinning disk as it orbits a large body like the Earth.

If you're not familiar, take a bike tire and find a way to hold the axle part of the wheel, then spin it real fast. Then, sit on a stool that can turn and turn the wheel. You'll start turning as the centrifugal force exerts itself.

ETA:

 
How to Calculate the Force of Gravity on the Earth’s Surface - dummies

You can use Newton’s law of gravitation to get the acceleration due to gravity, g, on the surface of the Earth just by knowing the gravitational constant G, the radius of the Earth, and the mass of the Earth. The force on an object of mass m1 near the surface of the Earth is

F = m1g

This force is provided by gravity between the object and the Earth, according to Newton’s gravity formula, and so you can write

331266.image1.png
<img src="https://www.dummies.com/wp-content/uploads/331266.image1.png" width="97" height="49" alt="image1.png"/>

The radius of the Earth, re, is about 6.38 × 106 meters, and the mass of the Earth is 5.98 × 1024 kilograms. Putting in the numbers, you have

331267.image2.png
<img src="https://www.dummies.com/wp-content/uploads/331267.image2.png" width="329" height="73" alt="image2.png"/>

Dividing both sides by m1 gives you the acceleration due to gravity:

331268.image3.png
<img src="https://www.dummies.com/wp-content/uploads/331268.image3.png" width="293" height="117" alt="image3.png"/>

Newton’s law of gravitation gives you the acceleration due to gravity near the surface of the Earth: 9.8 meters/second2.

Of course, you can measure g by letting an apple drop and timing it, but what fun is that when you can calculate it in a roundabout way that requires you to first measure the mass of the Earth?
I'm not sure this applies. We're talking centrifugal force as opposed to gravity.
Gravity is created by mass, of course centrifugal force is the topic.
 
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If spun, all the solar panels and extraneous bits would have to be built to endure the force.



:haha:


There is no force to build against. I thought you guys were all sciency. You have no clue what you're talking about.
 
Start at 24 minutes to get to the bottom line of a spinning disk and its force.

 
They would need to be magnetized.
Why? Isn't the point of false gravity to simulate light gravity and bypass the need for external measures?

I don't think the space station is designed for the perimeter to be used as a floor. That might be something to consider if another is built.
No doubt it isn't. I just don't get why. Cost? Technical restraints? Risk?
I think that there is an enormous cost to countering the gyroscopic effect of a spinning disk as it orbits a large body like the Earth.

If you're not familiar, take a bike tire and find a way to hold the axle part of the wheel, then spin it real fast. Then, sit on a stool that can turn and turn the wheel. You'll start turning as the centrifugal force exerts itself.

ETA:








This isn't being done in a vacuum. HUUUUUGE dif.
 
How to Calculate the Force of Gravity on the Earth’s Surface - dummies

You can use Newton’s law of gravitation to get the acceleration due to gravity, g, on the surface of the Earth just by knowing the gravitational constant G, the radius of the Earth, and the mass of the Earth. The force on an object of mass m1 near the surface of the Earth is

F = m1g

This force is provided by gravity between the object and the Earth, according to Newton’s gravity formula, and so you can write

331266.image1.png
<img src="https://www.dummies.com/wp-content/uploads/331266.image1.png" width="97" height="49" alt="image1.png"/>

The radius of the Earth, re, is about 6.38 × 106 meters, and the mass of the Earth is 5.98 × 1024 kilograms. Putting in the numbers, you have

331267.image2.png
<img src="https://www.dummies.com/wp-content/uploads/331267.image2.png" width="329" height="73" alt="image2.png"/>

Dividing both sides by m1 gives you the acceleration due to gravity:

331268.image3.png
<img src="https://www.dummies.com/wp-content/uploads/331268.image3.png" width="293" height="117" alt="image3.png"/>

Newton’s law of gravitation gives you the acceleration due to gravity near the surface of the Earth: 9.8 meters/second2.

Of course, you can measure g by letting an apple drop and timing it, but what fun is that when you can calculate it in a roundabout way that requires you to first measure the mass of the Earth?
I'm not sure this applies. We're talking centrifugal force as opposed to gravity.
Gravity is created by mass, of course centric all force is the topic.
yes, but a rotational force (centrifugal) is not a force created by mass but by motion. This motion has a force that can be applied. This is how gyroscopes work, but they are different forces.
 
They would need to be magnetized.
Why? Isn't the point of false gravity to simulate light gravity and bypass the need for external measures?
All objects with gravity are due to its magnetic core and the field of flux..Normally an iron core...Just like in yer transformers.
You've never stuck to the wall of a spinning barrel at an amusement park have you lol


that is not really gravity

if it was we all would be flung off the face of the earth
It's syntrifical force which is the same thing I'm talking about.

And if not for the gravity of the earths mass we would fly off as a result of the rotation.

actually centripetal force is what is required in your space ship to create artificial gravity
 
Start at 24 minutes to get to the bottom line of a spinning disk and its force.






Once again, this is NOT IN A VACUUM!

True, it's a crude example of the forces that must be dealt with regarding a spinning disk.

The entire system becomes even more complicated by the large centrifugal force, is linear speed regarding travel around the Earth, and the Earths influence upon the entire Station. All of these must be balanced in order to provide a form of gravity.
 
Why? Isn't the point of false gravity to simulate light gravity and bypass the need for external measures?
All objects with gravity are due to its magnetic core and the field of flux..Normally an iron core...Just like in yer transformers.
You've never stuck to the wall of a spinning barrel at an amusement park have you lol


that is not really gravity

if it was we all would be flung off the face of the earth
It's syntrifical force which is the same thing I'm talking about.

And if not for the gravity of the earths mass we would fly off as a result of the rotation.

actually centripetal force is what is required in your space ship to create artificial gravity
Ah.....Good catch.
 
Need magnetic boots............To stick to the side walls.............Then rotate the station to equal 9.8 m per second squared...........Amount of force would be mass times acceleration....???????
 

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