Science students need a problem too solve.

[Grumblenuts]

Finally I am learning again.
From the above I see
fluid pressure = (fluid density) X (acceleration due to gravity) X (fluid depth)

Can I equate 118,428 pounds = fluid pressure?
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"Hint: Does not apply here!" (statics)

 

[Grumblenuts]

one going down.
one going up.
Right opposite each other but going in opposite directions cancel their weight making this a mute problem.

Your system involves moving masses which may easily make the static weights relatively moot {not "mute"} in RL application. I'm no mechanical engineer. Finger it out or pay one.

 

[Grumblenuts]

Grumblenuts, tell me a little more about dynamics, etc
thanks in advance
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Listen to JoeMama. If you can gain anything with his(her?) much simpler setup then worry about yours.

 

[watchingfromafar]

Your system involves moving masses which may easily make the static weights relatively moot {not "mute"}

Thanks for the grammar lession

I'm no mechanical engineer. Finger it out or pay one.

It is "figure" not "finger"

Still the SeaEngine design is an interesting topic. Maybe not for you but hopefully for others
-

 

[Sunsettommy]

Is this that same shit about pumping air down to buckets? It won't work and it's a dumb idea.

And yet no one has proven that it will not work, no even you -

Bwahahahahahah!!!

All YOU have to do is PROVE that it works.........

still waiting for that..... when are YOU going to prove it?

Waiting...........

 

[Sunsettommy]

Many people, including myself have shown you that it won't work. The energy required to pump air to depth is more than could ever be gained by the ascending buckets, or balloons, or whatever enclosure you might use. The fact that there can only be a net loss of energy in such a system has been proven to a mathematical certainty.

No one here seems to be able to grasp the total system.

It takes (X) amount of energy to pump air down to the lowest bucket.

When that bucket is injected with air it will rise and the next bucket is injected with air

This process repeats itself until there are ten (10) buckets all pushing to get to the surface. And then the next bucket reaches the bottom and it too is injected with air continuously repeating the above. The energy output is the ten (10) buckets pulling together to reach the surface.

The energy required to keep the system running is to fill the lowest bucket with air.

BULLDOG; tell me where I went off the track into the swamp ?

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Not is YOU who hasn't shown that it works.... the onus is on You to show that it works.

I don't have to prove that you are wrong BECAUSE you are the one who brought it up, therefore it is YOU who has to prove it works.

 

[Crepitus]

Many people, including myself have shown you that it won't work. The energy required to pump air to depth is more than could ever be gained by the ascending buckets, or balloons, or whatever enclosure you might use. The fact that there can only be a net loss of energy in such a system has been proven to a mathematical certainty.

No one here seems to be able to grasp the total system.

It takes (X) amount of energy to pump air down to the lowest bucket.

When that bucket is injected with air it will rise and the next bucket is injected with air

This process repeats itself until there are ten (10) buckets all pushing to get to the surface. And then the next bucket reaches the bottom and it too is injected with air continuously repeating the above. The energy output is the ten (10) buckets pulling together to reach the surface.

The energy required to keep the system running is to fill the lowest bucket with air.

BULLDOG; tell me where I went off the track into the swamp ?

-

No.

A. The rising buckets lose energy pushing through the water. It is not a frictionless environment.

B. The energy required to keep the system running isn't the energy to fill the next bucket, but the energy to fill the next ten.

C. Since each bucket loses energy to friction on its way up there isn't enough energy in the system to keep going without external input.

So D. Get over it.