I Need Help Solving This Math Problem

Every number in power '0' is equal '1'.

Ahh, that’s a fun one… I’ll give it a shot.

We know that 6^1=6
This can also be expressed as a fraction
(6^2)/(6^1)=(6x6)/6=6

So if we divide it down get to 6^0 there are no more multiples in the numerator and we are left with it 6/6 which equals 1

Does that make sense?
That's correct.
Good answer.



I explain it through division and multiplication.

6° implies division by the same number, which equals 1.

7/7 = 1
11/11 = 1
x/x = 1

Why does 6° imply division by the same number, because of exponent rules.

6^4 divided by 6^4 = 6° , because 4-4 = 0, which equals 1.
 
That's correct.
Good answer.



I explain it through division and multiplication.

6° implies division by the same number, which equals 1.

7/7 = 1
11/11 = 1
x/x = 1

Why does 6° imply division by the same number, because of exponent rules.

6^4 divided by 6^4 = 6° , because 4-4 = 0, which equals 1.


I thought you meant 6 degrees. vs. Radians or something more complicated. Board typing is not good for math functions.
 
I do believe that we're supposed to use PEMDAS here but I'm not sure how to get the final answer. It's:

3x3-3Ć·3+3


Now according to PEMDAS you would multiply 3x3 and get nine and three divided by three is one, three plus three equals six and finally three minus three is zero but is that what we're even supposed to do here because I don't know how to get the final answer. šŸ¤”
Because according to how this is printed the answer is 11.

Look at it this way....due to how it is expressed:
(3Ɨ3)-(3Ć·3)+3
9-1+3
=11

Changing the brackets will radically change the answer. But with the way you originally printed the equation that's how it goes together.
 
I have never heard of PEMDAS so who made that rule and why is it considerd the correct way of doing math?
Would you use PEMDAS in a real work enviroment.
 
I have never heard of PEMDAS so who made that rule and why is it considerd the correct way of doing math?
Would you use PEMDAS in a real work enviroment.
Yes....
The entire electric grid is dependent upon good math skills.
Electricians only look dumb....we use algebra, polar addition, and trigonometry constantly.
I was told plumbers do...but I haven't seen any evidence supporting it.

Edited to add:
Engineers don't....they regularly put 2 4" electrical boxes at the same elevation (back to back) in 6" of a wall that supports a glass window and a door. It requires an electrician to figure out what really needs to go where to make things work.
 
Because according to how this is printed the answer is 11.

Look at it this way....due to how it is expressed:
(3Ɨ3)-(3Ć·3)+3
9-1+3
=11

Changing the brackets will radically change the answer. But with the way you originally printed the equation that's how it goes together.
So PEMDAS need to be used in all math equations?
 
So PEMDAS need to be used in all math equations?
For the formulas for which this applies....yes. (distributive mathematics and base8 are a little different for machine languages)

Trigonometry is also a bit different because the equations are based in theorems and postulates. So we use formulas for volume or arcs.
 
I have never heard of PEMDAS so who made that rule and why is it considerd the correct way of doing math?
Would you use PEMDAS in a real work enviroment.
Good point. I have heard of an Alternate Math system which is catching on quickly within Trump world. It is based on the following rule: Multiplication. Addition. Geometry. Addition.
Everything else gets ignored or is considered rigged or fake news.
 
Good point. I have heard of an Alternate Math system which is catching on quickly within Trump world. It is based on the following rule: Multiplication. Addition. Geometry. Addition.
Everything else gets ignored or is considered rigged or fake news.


Umm what does this thread have to do with Trump? Anyways my fiancee actually came up with five by solving the problem like this. So I now think that 11 is the wrong answer and that it actually is 5. As he seems to know what he's talking about.


3x3=9

3Ć·3= 1
1+3= 4

9-4= 5
 
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