Now molecules are getting absorbed?!?! I thought we were talking photons! How does an emitted photon "know" whether it's traveling from a hot-to-cold or vice versa? I think your point is ludicrous. If a photon gets re-emitted in the direction of earth, that IS transfer of energy. Did you expect us not to realize that? Your conception of AGW theory gets goofier by the minute!!!
Sorry. I was running out of time at lunch and failed to proof read my post. Clearly I didn't intend to say molecule. As to photons, they go nowhere on thier own. Depending on which text you read, they are either unable to move unless it is upon an electromagnetic field or they are the actual "stuff" that makes up the field. Here, I gave RWatt the definition of photon but as you clearly don't grasp what a photon is, I will provide them for you as well.
photon - The quantum of electromagnetic energy, regarded as a discrete particle having zero mass, no electric charge, and an indefinitely long lifetime.
For your reference, here is also a definition of quantum.
quantum - The smallest amount of a physical quantity that can exist independently, especially a discrete quantity of electromagnetic radiation.
You should be able to read that definition and grasp that a photon is not a free agent but is the smallest part of the electromagnetic fields that you just subtracted to zero. When yuo were subtracting, you were subtracting energy, photons; the whole of the EM field.
photon - a unit of energy in the form of light.
photon - a subatomic particle, having energy and momentum but no mass or electric charge, that is the quantum unit of electromagnetic radiation, including light
photon - a quantum of electromagnetic radiation
What you clearly don't grasp is that an EM field can not travel upstream against a stronger EM field. When you calculate the strength of the EM field emitted by the atmosphere and the strenght of the EM field emitted by the earth, it is clear that the field emitted by the earth is stronger. You must subtract the two fields and the stronger determines which direction the resulting field will be propagated. In the case of atmosphere vs earth, the earth has the stronger field so all energy is moving away from the earth except that which is coming in from the sun which is arriving as a stronger EM field than the earth emits.
If the weaker field from the atmosphere can not travel against the stronger field emitted from the earth then no photons from the atmosphere reach the earth. The definitions I gave you clearly indicate that photons are not free agents. They only go where the EM field they are associated with go.
Now feel free to do the math for yourself to prove that no energy transferrs from the atmosphere to the earth. Look back through the thread and you will find all the formulas, physical laws, and quantities necessary in both my own and RWatt's posts. He did the math and found that no energy transfer is possible between a cooler object and a warmer object. Your faith is no match for actual science or mathematics.