Why a Photon Moves at Lightspeed Directly After Being Emitted

does scattering require white light to be all the colors of the rainbow so that it can be scattered to show prominent colors?

Short answer: yes — scattering only redistributes what’s already there, it doesn’t create new colors.
But there’s an important nuance that makes this clearer.


What “white light” actually means​

White light is not a special substance. It just means:

a mix of many wavelengths across the visible spectrum.
The Sun’s light (before any atmosphere) already contains:

  • red
  • orange
  • yellow
  • green
  • blue
  • violet
So when people say “scattering,” they mean sorting, not generating.
 
you guys know scattering is a part of the late 19th century crackpotology that ruled, and explained what they were looking at and doing? Still exists today really.....
 
Spacetime don't need to absorb and emit: I postulate that spacetime can copy a particle onto a new position in space and erase the old copy instantaneously.
You have any math to support that?

Come on: the definition of isotropy is: "looking the same across spacetime" not across reference frames!
Not sure how you can look across spacetime without crossing some reference frames, for isn't it those reference frames which make up and define spacetime?
 
color is an effect of red shift or blue shift of yellow light. The frequency of yellow is increased or decreased by an energy increase or decrease. Spin of the planet like atom is what modulates the lights frequency into color.
 
Spacetime don't need to absorb and emit: I postulate that spacetime can copy a particle onto a new position in space and erase the old copy instantaneously.
If a photon has no mass, why would it have to be copied? Can't energy just be transmitted at the speed of light?
 
the frequency that light is emitted from the planet like atom is the speed at which the core of the atom emits and absorbs or cools and heats to create the waves. The core spins as a result of the wave structure of light and can add or decrease speed to the oscillation that creates the frequency changing color.
 
If a photon has no mass, why would it have to be copied? Can't energy just be transmitted at the speed of light?
Conservation of information.

When you destroy the old bit, you have to create a new one somewhere else. Otherwise Landauer says your universe heats up and you lose all the information.
 
Come on: the definition of isotropy is: "looking the same across spacetime" not across reference frames!

Physics joke:

Einstein died and went to heaven, where he met God.

He said, "there's something that's always bothered me. Why is the speed of light 3x10^8 m/sec?"

God looked at him puzzled, said "What do you mean? The speed of light is 1."

🥁
 
Not sure how you can look across spacetime without crossing some reference frames, for isn't it those reference frames which make up and define spacetime?
No, space isn't made of a conglomerate of reference frames and is not defined like that.

You have any math to support that?
Yes: p = p_xe_x+p_ye_y+p_ze_z
 
talanum1 how many frequencies are included? there are infinite divisions of color, so you'll have to ballpark a number, I'd go with 32. so of those 32 frequencies how does one pop out of the atom again?
 
If a photon has no mass, why would it have to be copied? Can't energy just be transmitted at the speed of light?

That's an interesting question. If you postulate a lattice then your spacetime is actually discrete. At 20 orders of magnitude lower resolution it may appear continuous but that doesn't mean it is.

What really suggests continuity is the distributions. The distribution of quantum states is perfectly random, not just to 20 orders of magnitude but all the way out to 73 digits.

Here's a heads up: if you have a discrete spacetime and you have to move a photon from one place to another, the heat from the destruction of the old information goes into the old node, not the new one. Any form of "borrowing" energy (like virtual particles) is tantamount to memory.
 
15th post
Any form of "borrowing" energy (like virtual particles) is tantamount to memory.
Come on: it has nothing to do with memory: a virtual particle pair can popup anywhere at random.
 
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