Sound experiment to prove red shift is caused by distance

[Sherlock Holmes]

at a frequency of 1479.99 hz I get the same two minute interference patterns that I get from the 15 foot recorder and the source. the difference is .01 hz at 15 feet from the 5 watts source, inverse square law would apply. I was trying to estimate the red shift caused by frequency that gets wider as you get further from the source, using the spherical area of expansion, considering the aether to be real, how to scale up the experiment to get accurate numbers for star distance measurements?

What is this "two minute interference pattern"?

Please provide some pairings of measured frequencies, like (1000, 5) and (997, 15) etc? Can you do that? Provide some actual examples of frequencies at different distances.

Are you claiming that with a tone of 1479.99Hz you measure a frequency change of 0.01Hz when the distance between source and receiver changes by 15ft? that's a difference of 0.00067 % how are you measuring the frequency? what equipment are you using? an oscilloscope? or what?

 

[trevorjohnson83]

What is this "two minute interference pattern"?

Please provide some pairings of measured frequencies, like (1000, 5) and (997, 15) etc? Can you do that? Provide some actual examples of frequencies at different distances.

Are you claiming that with a tone of 1479.99Hz you measure a frequency change of 0.01Hz when the distance between source and receiver changes by 15ft? that's a difference of 0.00067 % how are you measuring the frequency? what equipment are you using? an oscilloscope? or what?

the source frequency is 1480 hz, the frequency of the recorder is 1479.99 hz, I measure the two minute interference pattern on the sound editing program I use, I can visually see in the program the layout of the interference wave lasting two minutes.

 

[trevorjohnson83]

My original thought is that the car speeding away from you with its radio loud increases in the bending or red shift of the sound, but if the car stops, it stops at the point in the bending its at and stays there, rather than returning to the original appearance of the sound, it stays shifted. So distance alone causes red shift of light.

 

[Sherlock Holmes]

the source frequency is 1480 hz, the frequency of the recorder is 1479.99 hz, I measure the two minute interference pattern on the sound editing program I use, I can visually see in the program the layout of the interference wave lasting two minutes.

Interference arises from phase changes and the relative phases depend on distances but not the frequencies.

 

[trevorjohnson83]

Interference arises from phase changes and the relative phases depend on distances but not the frequencies.

the computer said this I don't understand, what am I assuming?

 

[trevorjohnson83]

15 feet away from the source loses power behind it but stays at a constant speed. How? the frequency changes to a weaker easier to propel as you expand away from the source.

 

[Sherlock Holmes]

15 feet away from the source loses power behind it but stays at a constant speed. How? the frequency changes to a weaker easier to propel as you expand away from the source.

This conversation can serve no further purpose.

 

[trevorjohnson83]

This conversation can serve no further purpose.

The relative phase shift depends on the specific frequencies involved and the time difference between the waves? seems you are wrong.

 

[trevorjohnson83]

Interference arises from phase changes and the relative phases depend on distances but not the frequencies.

?

 

[trevorjohnson83]

Sherlock Holmes I'll just mark your dropping out of the thread as a compliment to your posts you dropped out on it. moving on...

 

[trevorjohnson83]

My original thought is that the car speeding away from you with its radio loud increases in the bending or red shift of the sound, but if the car stops, it stops at the point in the bending its at and stays there, rather than returning to the original appearance of the sound, it stays shifted. So distance alone causes red shift of light.

any takers on this perfectly valid point that aren't grotesque troll comments on how smart you are?

 

[Sherlock Holmes]

Sherlock Holmes I'll just mark your dropping out of the thread as a compliment to your posts you dropped out on it. moving on...

Do as you wish, your claims are at odd with empirical data and school level physics. Even if you do a basic web search you'd learn that:

I asked you, what equipment are you using to measure the frequency? don't you even know that? why won't you tell me?

This is a science area not pseudo science just FYI.

 

[trevorjohnson83]

Sherlock Holmes eye candy in your responses smells delicious to you! but anyways I explained the experiment enough, why don't you answer the question about the car radio? That would redeem some of the things you dropped so far, which are totally you related. just saying.

 

[Sherlock Holmes]

To differentiate two sound frequencies 1480 and 1479.99 means you needed to count the differences (all frequency measuring devices are counters internally).

They don't count fractions of a cycle only complete cycles so you need to count 148000 cycles and 147999 cycles.

So you'd need to actual sample the signal for a minimum of 100 seconds to get a one cycle count difference at these frequencies.

 

[Sherlock Holmes]

Sherlock Holmes eye candy in your responses smells delicious to you! but anyways I explained the experiment enough, why don't you answer the question about the car radio? That would redeem some of the things you dropped so far, which are totally you related. just saying.

I asked you, what equipment are you using to measure the frequency? don't you even know that? why won't you tell me?

I suspect it is incapable of measuring the frequency to a resolution of 0.01 Hz that's why I'm asking I want to see the specs for the equipment you're using, I'm an electronics engineer and these are important factors - if you are serious that is...

 

[trevorjohnson83]

To differentiate two sound frequencies 1480 and 1479.99 means you needed to count the differences (all frequency measuring devices are counters internally).

They don't count fractions of a cycle only complete cycles so you need to count 148000 cycles and 147999 cycles.

So you'd need to actual sample the signal for a minimum of 100 seconds to get a one cycle count difference at these frequencies.

Online Tone Generator - generate pure tones of any frequency

www.szynalski.com

love this thing!

 

[Sherlock Holmes]

Online Tone Generator - generate pure tones of any frequency

www.szynalski.com

love this thing!

Well that's not how I'd generate a stable audio tone, I use one of these:

That lets you set a very precise frequency, e.g

That web-app is not calibrated and is likely not stable, not a pure sine (so likely has many harmonics in it) and if I had a microphone handy I'd actually measure it and show you.

But again, how are YOU MEASURUING the frequency 1479.99 ? what are you using?

 

[trevorjohnson83]

Well that's not how I'd generate a stable audio tone, I use one of these:

View attachment 1048397
That lets you set a very precise frequency, e.g

View attachment 1048398
That web-app is not calibrated and is likely not stable, not a purse sine and if I had a microphone handy I'd actually measure it and show you.

once in my crazy days I imagined a long time ago in the universe, a guy, me, invented the first oscillator to use for his guitar and he used like a spinning mirror and light, not so much a mirror but like different shiny colored surfaces that created effects on his guitar. I still wonder if that's possible.

 

[Sherlock Holmes]

once in my crazy days I imagined a long time ago in the universe, a guy, me, invented the first oscillator to use for his guitar and he used like a spinning mirror and light, not so much a mirror but like different shiny colored surfaces that created effects on his guitar. I still wonder if that's possible.

But again, how are YOU MEASURUING the frequency 1479.99 ? what are you using?

 

[trevorjohnson83]

But again, how are YOU MEASURUING the frequency 1479.99 ? what are you using?

Sony digital recorder, also you can type 1479.99 as the desired frequency in the tone generator.