tell me, when a photons energy is used to create heat (work) it can not be re-emitted at the same wave length because it has cooled.
The photon has cooled?
where are you getting magical photons from that do not expend energy in water?
Magic photons are SSDD's specialty. My photons are the standard type.
CO2 simply re-emits the photon instantaneously.
In all directions. Even toward the ground, right?
A photon emitted at 12um, absorbed by water vapor for 1 second will be re-emitted at about 15um, at 3 seconds it will be re-emitted at about 24um. This process is totally dependent on ambient air temp and the pressure differential of temperatures.
What does "pressure differential of temperatures" mean?
The emitted photon is at the wavelength of the object which emitted it. Water is cooler than other black bodies, therefore a warmer bodies emit a photon which is absorbed by the cooler object, in this case water, which will emit a photon at its temperature wavelength. The residency time of the photon and the temperature differential (pressure) will determine how much energy is used up during its time of residency.
In short, water absorbs energy and it emits it at a longer wavelength as the graph I showed you shows. Use some cognitive thinking skills and do the damn math...
The emitted photon is at the wavelength of the object which emitted it.
You might want to restate this, objects don't have wavelengths.
Water is cooler than other black bodies
Ummm....what?
In short, water absorbs energy and it emits it at a longer wavelength as the graph I showed you shows.
That graph didn't show water absorbing at one wavelength and emitting at another.
You didn't answer, what does "pressure differential of temperatures" mean?
And you ignored this....
CO2 simply re-emits the photon instantaneously.
In all directions. Even toward the ground, right?
Thanks for the chart.
Do you have one that backs up your claim?
water vapor absorbs, warms and re-emits at a slight longer wave length
lol..
tell me, when a photons energy is used to create heat (work) it can not be re-emitted at the same wave length because it has cooled. where are you getting magical photons from that do not expend energy in water? CO2 simply re-emits the photon instantaneously. it therefore does little or no work.
For instance.. LWIR is absorbed by the water molecule. Because it resides inside for a long period of time before it is re-emitted, it causes vibrations of the molecule and collisions with other molecules. This is work and expends some of the energy of the photon. The longer it resides the more energy is expended. The photon emitted will be of the lower temperature and thus a longer wave length.
A photon emitted at 12um, absorbed by water vapor for 1 second will be re-emitted at about 15um, at 3 seconds it will be re-emitted at about 24um. This process is totally dependent on ambient air temp and the pressure differential of temperatures.
You keep screaming about "smart photons" but it is not so much smart as it is the inter-dynamics of different molecules defined by the natural laws.
Hahahaha. There is nothing correct in that last comment. Usually you get something a little bit right, probably by accident, but this time everything was wrong and by a large margin.
Were you drinking or something?
You two kill me...
Photons are emitted in all directions from all molecules. The laws of thermal dynamics (Natural Laws) indicate that a colder object has no effect on a warmer object. You can bitch about why that happens "smart Photons" all you want, but the physical laws show that there is no observable, quantitative effect.
You make statements, as if they were fact, due to models that are untestable and have no observed evidence to support them. they are simply unproven hypothesis.
Water vapor reactions and energy residency times are just now becoming understood. One paper being done by the Colorado Atmospherics lab used narrow band width LWIR and injected it into a body of water vapor (cylindrical glass tube 100' long) taking note of the increase of LWIR and in what bands at various distances from the source. At just 40% humidity, LWIR sent at 16-18um showed a positive response at 22-26um. After 24 hours in a room at 80 deg F the tube had no warming. If CO2 had the powers you all like to tout then the tube should have warmed. The energy used was equivalent to 235w/m^2 striking the surface of the earth, contained in that bandwidth. Even when it was expanded to 14um-22um (the full spectrum of CO2's possible positive forcing) the spike in radiated energy was in the 22-49um regions.
SO why would water not immediately respond by radiating the same wave length that it absorbed? What causes this?
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