Does this experiment prove ether?

rupol2000

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Aug 22, 2021
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Suppose a person is in a box. If he tries to lift this box together with himself, by pressing on the top, he will not be able to do this, because the pressure will be distributed in both directions. This roughly corresponds to Newton's 3 laws.
Imagine now that a person jumps up, waits for the end of the "inertial" movement and hits the top cover. Thus, he will complete the task, and the 3rd law will not work.
The question arises, what does it rely on while hanging in the air at the moment of impact, why are the forces not distributed as in the first case?
The answer may be that this is possible thanks to the ether, which serves as a support for its push. If there was no ether there, it would simply bounce off the top cover.
 
Work is force times distance. In the first case there is no movement, so there is no work.

If he pushes on the top at the apex of his jump the box will accelerate up and he will accelerate down faster than gravity would ordinarily accelerate him. His force up is equal to the inertial resistant force of the box. Forces are balanced. Work is done. Momentum is conserved.
 
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Work is force times distance. In the first case there is no movement, so there is no work.

If he pushes on the top at the apex of his jump the box will accelerate up and he will accelerate down faster than gravity would ordinarily accelerate him. His force up is equal to the inertial resistant force of the box. Forces are balanced. Work is done. Momentum is conserved.
What does work have to do with it? It's about action, not work. Whether the energy will go into work or not is generally another question, in the case of a jack there will be work in this situation.
 
Newtons action is not violated, In the first case it is a static problem. Trivial.
In the second case there is equal force of the person against the box top and the box top against the person.

Your question why aren't the forces distributed .... They are distributed in both cases.
 
Suppose a person is in a box. If he tries to lift this box together with himself, by pressing on the top, he will not be able to do this, because the pressure will be distributed in both directions. This roughly corresponds to Newton's 3 laws.
Imagine now that a person jumps up, waits for the end of the "inertial" movement and hits the top cover. Thus, he will complete the task, and the 3rd law will not work.
The question arises, what does it rely on while hanging in the air at the moment of impact, why are the forces not distributed as in the first case?
The answer may be that this is possible thanks to the ether, which serves as a support for its push. If there was no ether there, it would simply bounce off the top cover.

I suppose it is possible that ether may have had something to do with causing this post. If you're huffing not quite enough of it to render you unconscious, but just short of that, your brain might be in a fucked-up-enough state to cause you to write the above.
 
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Newtons action is not violated, In the first case it is a static problem. Trivial.
This is the third law in action, when ether is not taken into account. Action is equal to reaction, and the pressure is distributed between the two sides, which does not work in the second case.
 
This is the third law in action, when ether is not taken into account. Action is equal to reaction, and the pressure is distributed between the two sides, which does not work in the second case.
When you push against a box you feel the inertia of the box. That force makes you move away from the box. The force on the box makes it move away from you. That also happens when there is no gravity. Your push makes you and the box recede from each other. The final velocity of you and the box is given by the conservation of momentum law which is dependent on the relative masses.

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