Wow.. A lot of nibbling at definitions there. HEAT propagates through matter and materials by means of convection (heat differentials) or conduction (direct molecule to molecule PHYSICAL transfer of energy).
Propagate is the correct physics term. Light (of which IR is a subset) doesn't NEED matter or materials to propagate. It propagates as defined by the geometry of the emitter and travels without regard for temperature. Because IR "heat" is not heat unless it is absorbed by matter that is CAPABLE of absorbing it at that energy level and wavelength.
Please provide a proper definition for "propagation" :
This Merriam Webster ..............
propagation
noun prop·a·ga·tion \ˌprä-pə-ˈgā-shən\
Definition of PROPAGATION
: the act or action of
propagating: as
a : increase (as of a kind of organism) in numbers
b : the spreading of something (as a belief) abroad or into new regions
c : enlargement or extension (as of a crack) in a solid body
Which of those would you like to try and fit into this conversation.
It really is simple, a printed ACCEPTED definition that you would like to use from a reputable source.
"Retarding net heat loss" simply means that the cooler body has some IR emissions of it's own that are directed to the warmer body. And that energy will land and CONVERT to heat regardless of the temperature.
Link to that assertion please.
Who mentioned "retarding net heat loss" are you thinking of some other conversation or just dancing for us??
NO, once again, objects have "heat signatures" but radiate implies to give off and the object which receives the radiation warms up.
Nope, it ain't happening and there is every scientific principle against you and zero for you.
More song and dance though, let's continue.
But since each body has the other in it's OPTICAL PATH -- there will be an EXCHANGE of IR Radiative energy such that the Warmer body WINS. But it WINS in the net flux transfer only to the extent that the flow from the cooler body reduces it
Optical path :
op·ti·cal
ˈäptək(ə)l/
adjective
adjective:
optical
- 1.
of or relating to sight, especially in relation to the physical action of light.
"optical illusions"
- constructed to assist sight.
- devised on the principles of optics.
- 2.
Physics
operating in or employing the visible part of the electromagnetic spectrum.
"optical telescopes"
op·ti·cal path
noun
Physics
noun:
optical path; plural noun:
optical paths
- the distance of the path that in a vacuum would contain the same number of wavelengths as the actual path taken by a ray of light traveling through a medium.
From Wikipedia.
Which bodies are you eluding to??
Hey --- lighten up here. You are out on the desert and night falls. Not a cloud in the sky.. How COLD is it gonna get compared to a sky that it is clouded? THAT -- is the backradiation part of Radiative transfer. Because water vapor (clouds) are the DOMINANT greenhouse gas. The clouds "insulate" the ground. But they don't do that by actual HEAT TRANSFER. They do it by Radiative transfer. As a body, they can emit IR proportional to their warmer temperature (than a clear sky) and RETARD the loss of heat at the surface.. But the surface will ALWAYS cool with respect to the exchange. Just cools SLOWER with clouds raining down IR energy...
I am being light.
You are no different than anyone else, if your story don't fly, it don't fly.
Here you want to come out and act all technically superior bur fail to realize the simple concept of cloud cover??
I guess all these scientific based results that I have been debunking your mumbo jumbo line with don't exist.
Effects of Cloud Cover on forecasted temperatures
During the day, the earth is heated by the sun. If skies are clear, more heat reaches the earth's surface (as in the diagram below). This leads to warmer temperatures.
However, if skies are cloudy, some of the sun's rays are reflected off the cloud droplets back into space. Therefore, less of the sun's energy is able to reach the earth's surface, which causes the earth to heat up more slowly. This leads to cooler temperatures.
Forecast Tip:
When forecasting daytime temperatures, if cloudy skies are expected, forecast lower temperatures than you would predict if clear skies were expected.
At night cloud cover has the opposite effect. If skies are clear, heat emitted from the earth's surface freely escapes into space, resulting in colder temperatures.
However, if clouds are present, some of the heat emitted from the earth's surface is trapped by the clouds and reemitted back towards the earth. As a result, temperatures decrease more slowly than if the skies were clear.
So one last question, based on the simple pictures above, how does this tie into your assertions??
You do realize as weather changes or just through sheer physical principles the heat still escapes just at a different rate and time.