ChemEngineer
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- Feb 5, 2019
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- #21

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That is so funny. I also cut my refrigerator water filter open. I did mine after three years. It still had plenty of life left.I was taught ( engineering major) that both ice and water are usually present at 0 degrees C (one atmosphere of pressure). It is very difficult to maintain only ice at 0 degrees C or only water at 0 degrees C.
Big Joe, in an unusual combination of mechanical and chemical engineering, I just replaced my refrigerator water filter after 6 1/2 years of constant use. (Manufacturers recommend changing it every six months, so I was only off by just over one order of magnitude, but who's counting.)
I cut both ends off with a hacksaw, resulting in fine white plastic particles, not contaminants from the filter. Then I sliced the carbon filter with a razor blade and there was absolutely nothing visible that the filter captured.
Obviously water filters don't do much but they're pretty expensive. The new one was $25.
Tap water won't kill ya. Gramma and grampa grew up on it.
View attachment 452976
The activated carbon may have adsorbed some trace chemicals and lost their adsorptive capacity. We survived, somehow.
No calcs?! Okay, that's tough. I won't calc in my head; I will guesstimate...If you add a liter of water at the boiling point, 100 degrees Celsius, to a liter of water at its freezing point, 0 degrees Celsius, you obviously get two liters at 50 degrees C.
1) Without doing any calculations what is your best guess of what the equilibrium temperature is when you add a liter of water at 100 C to a liter frozen into ice at 0 C?
2) Now what is your best guess of what the equilibrium temperature is when you add three liters frozen into ice at 0 C to a kilogram (liter of water) of steam at 100 C in a perfectly insulated container?
The answers are amazing.
The problem will be removing them after driving that long. I know people who have done it and heard about it on Car Talk as well. The gasket will absolutely attach to the gasket mounting surface, and most oil filter wrenches will not be able to remove it.What is so obviously true of refrigerator water filters is likewise true of automotive oil filters. I hacksawed mine open after 5,000 miles and although the dirty oil blackened the paper, the amount of solids filtered by the paper was miniscule. I'd say you can replace your auto oil filters once ever 20,000 to 40,000 miles and save quite a bit, provided that you empty the dirty oil out of the filter and then replace it.
Now calcs, but just estimates...No calcs?! Okay, that's tough. I won't calc in my head; I will guesstimate...If you add a liter of water at the boiling point, 100 degrees Celsius, to a liter of water at its freezing point, 0 degrees Celsius, you obviously get two liters at 50 degrees C.
1) Without doing any calculations what is your best guess of what the equilibrium temperature is when you add a liter of water at 100 C to a liter frozen into ice at 0 C?
2) Now what is your best guess of what the equilibrium temperature is when you add three liters frozen into ice at 0 C to a kilogram (liter of water) of steam at 100 C in a perfectly insulated container?
The answers are amazing.
Heat of fusion 330 J/g
Heat of vaporization 2250 J/g
Heat capacity 4200 J/gK
Not doing any calcs at all, I will guess
1) 40C
2) I find this one quite challenging to guestimate, since there is a mass difference...
The steam condensation still takes more energy than melting the larger amount of ice, so I will guess 60C.
Now I will go read the subsequent posts and find out how wrong I am.
I would prefer to do the calcs, since they are quite simple.
If I am drinking it, it is half empty.
Now calcs, but just estimates...No calcs?! Okay, that's tough. I won't calc in my head; I will guesstimate...If you add a liter of water at the boiling point, 100 degrees Celsius, to a liter of water at its freezing point, 0 degrees Celsius, you obviously get two liters at 50 degrees C.
1) Without doing any calculations what is your best guess of what the equilibrium temperature is when you add a liter of water at 100 C to a liter frozen into ice at 0 C?
2) Now what is your best guess of what the equilibrium temperature is when you add three liters frozen into ice at 0 C to a kilogram (liter of water) of steam at 100 C in a perfectly insulated container?
The answers are amazing.
Heat of fusion 330 J/g
Heat of vaporization 2250 J/g
Heat capacity 4200 J/gK
Not doing any calcs at all, I will guess
1) 40C
2) I find this one quite challenging to guestimate, since there is a mass difference...
The steam condensation still takes more energy than melting the larger amount of ice, so I will guess 60C.
Now I will go read the subsequent posts and find out how wrong I am.
I would prefer to do the calcs, since they are quite simple.
1)
Melting ice: 330 kJ
330 kJ / 4.2 kJ/gK / 2000g = 0.04C
50C - 0.04C = 50C (slightly less than 50C, but not significant)
Wow, that is amazing.
Of course, if getting a precise answer was important, I would use m c delta-T and all that properly.
2)
Melting ice: 990kJ
Condensing steam: 2250 kJ
Delta (net energy) = 1260 kJ
1260 kJ / 4000g / 4.2 kJ/gK = 0.075K
Estimate of equilibrium temp w/o phase changes: 3*0 + 100 = 25C
25C + 0.075K = 25.1C
That is amazing as well.
If I messed up by a factor of 1000 somewhere, I would not be surprised.
If you add a liter of water at the boiling point, 100 degrees Celsius, to a liter of water at its freezing point, 0 degrees Celsius, you obviously get two liters at 50 degrees C.
Without doing any calculations what is your best guess of what the equilibrium temperature is when you add a liter of water at 100 C to a liter frozen into ice at 0 C?
Now what is your best guess of what the equilibrium temperature is when you add three liters frozen into ice at 0 C to a kilogram (liter of water) of steam at 100 C in a perfectly insulated container?
The answers are amazing.
Steam can be superheated, so I wouldn't take that as a general rule.Seventy-two views and only one guess by JoMoma.
Don't be afraid to guess wrong, people.
A gram of ice melts while absorbing 80 calories which cools the hot water from 100 to 20 C.
Equal quantities of 20 C water and 0 C water equilibrate at 10 degrees C. (Heat of fusion = 80 cal/gram)
Now add one pound, ton, or gram of ice at 0 degrees Celsius while piping in a like amount of steam at 100 degrees C and what do you think the equilibrium temperature will be? (It’s crazy.)
The first gram of steam entirely melts all the equal amount of ice while losing only 80 calories. It then loses another 100 calories raising the temperature from 0 to 100. All the water and steam are 100 degrees C. Another two grams of ice can be added and the final equilibrium temperature of 3 grams, or pounds, or tons of ice with 1 gram, pound, or ton of steam, will all be at 100 degrees C, the boiling point.
(Heat of vaporization is 540 calories per gram)
1 unit of steam melts and heats 3 units of ice to its temperature of water’s boiling point.
No, you got it backwards. IT IS a general rule, for we are talking about standard pressure.Steam can be superheated, so I wouldn't take that as a general rule.