srdanova math

Discussion in 'Science and Technology' started by msbiljanica, Jan 14, 2012.

  1. msbiljanica
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    msbiljanica Member

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    SRDANOVA MATHEMATICS
    Revision of the current mathematics
    $a1.jpg
    Marjanovic Srdan
    M.Biljanica
    16201 Manojlovce
    Serbia
    ms.biljanica@gmail.com
    Introduction: I think that the current limited maths and sinful and should be reviewed with all new
    things that I discovered. I will explain the mathematical space with two starting points ( along the
    natural and real ).

    Natural Base:
    Natural along is what you see along the fig,1.Natural along has its beginning and its end , this
    property natural long we will contact points ( fig.2).Natural length along the ground ( natural
    meaning).Two more natural and longer merge points
    $a2.png
    [S1]-along nature (fig. 1-a), [Sn]-mathematical facts
    [S2]-point ( natural meaning , Fig.2 -A(B))
    The points will mark capital letters along the (length) small letters
    Definition of - teo points A,B , the length between points AB
    CM (current mathematics) - does not recognize the concept of nature along , the point is not
    defined so that all l everything
    __________________________________________________ ___________
    Presupposition-Natural long - merge points in the direction AB
    Process:
    P1-AB..CD..ABC(AC)
    to read: natural along AB to point B, is connected to the natural long CD to point C, shall be
    renaming of points, we get along ABC (AC)
    P2-ABC (AC) .. DE ..ABCD (AD)
    read it: along the ABC (AC) to point C, connecting with the natural long-DE to point D is done
    renaming of points, we get along ABCD(AD)
    P3-ABCD (AD) ..EF .. ABCDE(AE)
    ...
    $a3.png
    [S3]-along (from natural long, two or more)
    Definition of the initial-and the last point, the length between the initial and final points.
    CM-I do not know the connection of natural longer, not along the natural base, but the real (the line , proof)
     
  2. Mr. H.
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    Mr. H. Diamond Member

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    Math is sinful. Now I've heard it all.
     
  3. msbiljanica
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    msbiljanica Member

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    Presupposition - All points of a longer (the infinite form) can be replaced with labels: (0), (0.1),
    ...,( 0,1,2,3,4,5,6,7,8,9 ),...
    The process:
    P1-N(0)= {0,00,000,0000,...}
    P2-N(0,1)= {0,1,10,11,100,...}
    ...
    P10-N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11, ...}
    ...
    $a4.png
    [S4]-numeric along
    [S5]-set of natural numbers N
    We will use N (0,1,2,3,4,5,6,7,8,9) = {0,1,2,3,4,5,6,7,8,9,10,11,12 ,...}
    Definition of-numeric along a starting point, the last point at infinity
    -The number 0 is the point 0
    -Other numbers are longer, the first item is 0, the last point is the point of the name (number)
    SM-I know the term but long term numeric numeric rays (line)
    Natural numbers and zeros are given axiom
    ________________________________________________________
    Presupposition-point numbers have their
    The process:
    P1-0 = (.0)
    P2-1 = (.0,1)
    P3-2 = (.0,1,2)
    P4-3 = (.0,1,2,3)
    P5-4 = (.0,1,2,3,4)
    ...
    $a5.png
    [S6]-point number
    CM-I do not know the item number
    _________________________________________________________________
    Presupposition-point numbers have opposite
    The process:
    P1-0 = (s.0)
    P2-1 = (s.0, 1)
    P3-2 = (s.0, 1.2)
    P4-3 = (s.0, 1,2,3)
    P5-4 = (s.0, 1,2,3,4)
    ...
    $a6.png
    [S7]-opposite point of
    CM-I do not know the opposite point of
     
  4. Colin
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    Colin Gold Member

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    T x 2 + W + A = TWAT
     
  5. msbiljanica
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    msbiljanica Member

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    Presupposition-numbers are comparable with each other
    The process:
    P1-two numbers (a, b) are comparable with each other - a> b, a = b, a <b, ).(=(>,=,<)
    P2-three numbers (a, b, c) are comparable with each other
    $a7.png
    P3-four numbers (a, b, c, d) are comparable with each other
    $a8.jpg
    ...
    [S8]-comparability issues
    CM-known two of comparability, comparability of three numbers (a number comparable with the number of the PC),comparability of the other knows.
    _____________________________________________________________________________
    Presupposition-number ranges number along
    The process:
    P1-image
    P2-image
    P3-image
    ...
    $a9.png
    [S9]-mobility of number
    CM does not know the number of mobility
     
  6. msbiljanica
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    Presupposition-Number (a) and mobile number (b ) of a contat ,merge
    Proces:
    P1 3+(.0/.0)2=3
    P2 3+(.1/.0)2=3
    P3 3+(.2/.0)2=4 - image
    P4 3+(.3/.0)2=5
    $a10.png
    designation means the more we write (.0/.0) , unless specifically indicated to be
    P1 3+(.0)2=3
    P2 3+(.1)2=3
    P3 3+(.2)2=4
    P4 3+(.3)2=5
    General form
    a+(.0)b=c
    a+(.1)b=c
    ...
    a+(.d)b=c
    [S10]-addition
    CM-only form a+(s.0/.0)b=c , others do not know , axiom
    ______________________________________
    Presupposition-Number (a) and mobile number (b ) but have no contact with the item
    Process:
    P1 ¤3(0)2¤
    P2 ¤3(1)2¤
    P3 ¤3(2)2¤
    ...
    $a11.png
    Next - gap number and mobile number have no contact , except to point
    ...
    [S11]-gap number GN={¤a(b)c¤,...,¤g(f)...(d)e¤}
    [S12]-gap along
    Definition[gap along] a>0-¤0(0)0¤-point
    -¤0(a)0¤-two point ,separated by a gap
    -¤a(0)0¤,¤0(0)a¤,¤a(0)a¤-along , two points
    -¤a(a)a¤-two along , 4 points
    ...
    CM-[S11],[S12] -does no know
    ______________________________________________
    Third Now we can describe ( c ) the number of gaps ,¤10m(5m)5m¤
     
  7. msbiljanica
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    Presupposition-Gap number is comparable with the gap number and number
    Process:
    P1 ¤a(b)c¤ , a+(s.0)c=z
    P2 ¤a(b)c(d)e¤ , a+(s.0)c+(s.0)e=z
    P3 ¤a(b)c(d)e(f)g¤ ,a+(s.0)c+(s.0)e+(s.0)g=z
    ...
    number z as it compares as a number of
    [S13]-comparability gap numbers
    CM-[S13]-does no know
    __________________________________________________
    Presupposition-Adding the result can be written in short form:
    a) a+(s.0)0 , a+(s.0)b , a+(s.0)b+(s.0)b , ...,a+(s.0)b+...+(s.0)b
    b ) a+(s.0)b+...+(s.0)b,...,a+(s.0)b+(s.0)b, a+(s.0)b , a+(s.0)0
    Process:
    P1 - 3+(s.0)0=3 , 3+(s.0)4=7 , 347
    3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3411
    3+(s.0)0=3 , 3+(s.0)4=7 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4+(s.0)4+(s.0)4=15 , 3415
    ...
    3+(s.0)0=3 , ... , 3+(s.0)4+...+(s.0)4=d , 34

    P2 - 3+(s.0)4+(s.0)4+(s.0)4=15 , 3+(s.0)4+(s.0)4=11 , 3+(s.0)4=7 , 3+(s.0)0=3 , 1543
    ...
    3+(s.0)4=7 , 3+(s.0)0=3 , 743
    General form -abc , ab
    [S14]-srcko
    CM-[S14]-does no know
     
  8. msbiljanica
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    msbiljanica Member

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    Presupposition-Srcko can join a number not that can not be in the structure srcko
    Process:
    P1 101070 and 5 , 5_101070
    P2 5520 and 22 ,5520_22
    P3 75 and 25 , 75_25
    P4 68 and 2 ,2_68
    ...
    General form -abc_d , d_abc , ab_d ,d_ab...
    [S15]-pendant srcko
    CM-[S15]-does no know
    Note-only one number can be pendand , number two goes into a complex srcko
    __________________________________________________________
    Presupposition-Two ( more ) srcko (pendand srcko) are combined into one unit
    Process:
    P1 106 and 118 , 106118
    P2 10565 and 703 ,10565_703
    P3 30360 and 45277_78 ,30360_45277_78
    ...
    General form -abcd , abc_de ,abc_def_g ,...
    [S16]-two ( more) srcko
    CM-[S16]-does no know
     
  9. Colin
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    Colin Gold Member

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    You clearly believe in making little things count. Ever considered teaching arithmetic to dwarves?
     
  10. msbiljanica
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    Presupposition-Two ( more ) srcko have the first ( last) common number
    Process:
    P1 10530 and 3330 , 10533(_30)
    P2 4444 and 441094 and 44256 , 44(_44_)1094256
    ...
    General form -abcd(_e) , ab(_c_)defg , ...
    [S17]-two ( more) first-last srcko
    CM-[S17]-does no know
    ______________________________________________________
    Presupposition-In the expression a+(.b)c=d , d+(s.0)11 or d+(s.0)number (more) from 11
    Process:
    P1 3+(.s.0)5=8+(s.0)11 , 3+(s.0)5<91
    P2 5+(.0)5=5+(s.0)224 , 5+(.0)5<729
    ...
    General form - a+(.b)c=d+(s.0)11 ,a+(s.b)c<e1
    a+(.b)c=d+(s.0)e , a+(.b)c<f
    a+(.b)c=d+(s.0)efg , a+(.b)c<hij ...
    [S18]-left inequality
    CM-[S18]-know
    _______________________________________
    2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
    2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
    2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94
    srcko
    5550={5,10,15,20,25,30,35,40,45,50}
    38350={38,41,44,47,50}
    501090={50,60,70,80,90}
    50792={50,57,64,71,78,85,92}
    two(more) first-last srcko
    55383(_50_)1090792
    remains part of the function, when we come to it
     

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