Awareness is no more a requisite for emitters and energy than it is for rocks falling to earth......again, logical fallacy...since I pointed out the argument to ridicule fallacy to you did you decide to try it out?...it is still a fallacy. Since all observations are of energy moving in one direction, you have nothing with which to support your belief other than an unobservable, unmeasurable, untestable mathematical model.
Since all observations are of energy moving in one direction
Here let me remind you of what the top physicists and institutions have to say about P = zero. Why do you think you know more than they do?
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Wilhelm Wien Nobel Prize speech.
http://www.nobelprize.org/nobel_prizes/physics/laureates/1911/wien-lecture.html
"[Equilibrium state] ... taken as a whole for many atoms in the stationary state, the absorbed energy after all becomes equal to that emitted..."
Optical Design Fundamentals for Infrared Systems Max J. Riedl
“at thermal equilibrium, the power radiated by an object must be equal to the power absorbed.”
http://spie.org/publications/optipe...t/tt48/tt48_154_kirchhoffs_law_and_emissivity
Gustav Robert Kirchhoff (1824–1887) stated in 1860 that “at thermal equilibrium, the power radiated by an object must be equal to the power absorbed.”
https://pediaview.com/openpedia/Radiative_equilibrium
In physics, radiative equilibrium is the condition where a steady state system is in dynamic equilibrium, with equal incoming and outgoing radiative heat flux
Thermal equilibrium | Open Access articles | Open Access journals | Conference Proceedings | Editors | Authors | Reviewers | scientific events
One form of thermal equilibrium is radiative exchange equilibrium. Two bodies, each with its own uniform temperature, in solely radiative connection, will exchange thermal radiation, in net the hotter transferring energy to the cooler, and will exchange equal and opposite amounts just when they are at the same temperature.
What Causes the Greenhouse Effect? « Roy Spencer, PhD
Kirchhoff's law is that for an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium, the emissivity is equal to the absorptivity.
http://bado-shanai.net/Map of Physics/mopKirchhoffslaw.htm
Imagine a large body that has a deep cavity dug into it. Imagine further that we keep that body at some absolute temperature T and that we have put a small body at a different temperature into the cavity. If the small body has the higher temperature, then it will radiate heat faster than it absorbs heat so that there will be a net flow of heat from the hotter body to the colder body. Eventually the system will come to thermal equilibrium; that is, both bodies will have the same temperature and the small body will emit heat as fast as it absorbs heat.
Albert Einstein: "... Even in thermal equilibrium, transitions associated with the absorption and emission of photons are occurring continuously... "
This is what Max Planck said in 1914.
http://www.gutenberg.org/files/40030/40030-pdf.pdf
Page 31: The energy emitted and the energy absorbed in the state of thermodynamic equilibrium are equal, not only for the entire radiation of the whole spectrum, but also for each monochromatic radiation.
Page 50: "...it is evident that, when thermodynamic equilibrium exists, any two bodies or elements of bodies selected at random exchange by radiation equal amounts of heat with each other..."
In Support of the A in AGW
So lets see a measured observation of energy moving both ways....oh, what's that? There are none?...OK.
So lets see a measured observation of energy moving both ways
Here you go, a graph of downward long-wave radiation over several 24 hour periods.
And when you get a chance, you never have explained how your one-way flow works while the cooler surface of the Sun emits toward the much hotter corona of the Sun.