are supernovae remnants visibly different than planetary nebulae? are supernovae based on a star's size, is size based on parallax view?
ChatGPT said:
Thought for 10 seconds
1. Visual Differences: Supernova Remnants (SNR) vs. Planetary Nebulae (PN)
- Morphology & Symmetry
- PN are typically small (ā¼0.1ā1 pc), symmetric shells or rings blown off by low-mass stars. They often show smooth, rounded shapes (spherical, elliptical or bipolar).
- SNR are larger (several pc), highly irregular and filamentaryāshocked ejecta plowing into the interstellar medium produces tangled filaments and arcs. nisenet.orgAstronomy Notes
- Central Object
- PN harbor a hot white dwarf in their center, often visible in optical/UV images.
- SNR may contain a neutron star or pulsar (or a black hole) that is usually faint against the bright, shock-heated shell. Astronomy Stack Exchange
- Emission Mechanism
- PN glow primarily by photo-ionization (UV light from the white dwarf excites the shellāstrong O III, H α lines).
- SNR shine by shock-heating and synchrotron emission (high [S II]/H α ratios; strong radio and X-ray signatures). Astronomy Notes
2. What Governs a Starās Supernova Type & How āSizeā Is Determined
- Progenitor Mass (āSizeā)
- Core-collapse (Types II, Ib/c): Stars with initial masses ā³ 8 Mā end their lives in a supernova once fusion can no longer support the iron core.
- Type Ia: A 1.4 Mā white dwarf in a binary accretes mass until runaway carbon fusion detonates it.
- Measuring Stellar āSizeā via Parallax
- Parallax ā Distance: Missions like Hipparcos/Gaia measure a starās annual parallax angle to determine its distance, ddd.
- Brightness + Distance ā Luminosity: Observed flux FFF yields absolute luminosity L=4Ļd2FL=4\pi d^2FL=4Ļd2F.
- Luminosity + Temperature ā Radius: Using the StefanāBoltzmann law,
L=4ĻR2ĻTeff4ā¹R=L4ĻĻTeff4ā. L = 4\pi R^2\sigma T_{\rm eff}^4 \quad\Longrightarrow\quad R = \sqrt{\frac{L}{4\pi\sigma T_{\rm eff}^4}}\,.L=4ĻR2ĻTeff4ā¹R=4ĻĻTeff4L.
Thus, āsizeā (radius) depends on distance from parallax, measured brightness, and spectroscopic temperature.
So yesā
a starās mass (and thus āsizeā) determines which kind of supernova it can undergo, and we infer that size through parallax-based distance measurements combined with photometry and spectroscopy.
Sources
o4-mini
You said:
why do supernovae remnants surround the core remnant if the shockwave should carry it all away pretty darn quick?
ChatGPT said:
Thought for 13 seconds
Because the explosionās blast starts
from the collapsing core itself and pushes the
starās envelope outward, the expelled material naturally
expands as a shell centered on the new compact remnant. Hereās why that shell remains visible around the core:
- Shock Launches Inside Out
- The core collapse and bounce create a shock right at the boundary between the protoāneutron star and the overlying mantle. That shock plows outward, accelerating the envelope while the core stays put. Wikipedia
- Core Receives Only a Small āKickā
- Neutron stars often get a natal kick of a few hundred km/s, but the ejecta travels at thousands of km/s. The bulk of the mass is thrown off symmetrically, so it always expands in a roughly spherical shell around the (nearly stationary) remnant. A&A
- Deceleration by Interstellar Medium
- As the ejecta runs into surrounding gas, it slows and piles up into a thin, dense shellāwhat we observe as the supernova remnant (SNR). That shell continues to surround the central neutron star or black hole as it coasts outward. Wikipedia
- Reverse Shock
- A reverse shockāāāformed when the forward shock slows in the ISMāāāpropagates back inward, heating inner ejecta and further defining the hollow shell structure that keeps the remnantās āwallā around the core. HEASARC
So even though the material is driven away at high speed, it is always launched
around the core. From our vantage, we see that expanding shell still centered on the compact remnantājust like a balloon being inflated around a seed.are supernovae remnants visibly different than planetary nebulae? are supernovae based on a star's size, is size based on parallax view?
ChatGPT said:
Thought for 10 seconds
1. Visual Differences: Supernova Remnants (SNR) vs. Planetary Nebulae (PN)
- Morphology & Symmetry
- PN are typically small (ā¼0.1ā1 pc), symmetric shells or rings blown off by low-mass stars. They often show smooth, rounded shapes (spherical, elliptical or bipolar).
- SNR are larger (several pc), highly irregular and filamentaryāshocked ejecta plowing into the interstellar medium produces tangled filaments and arcs. nisenet.orgAstronomy Notes
- Central Object
- PN harbor a hot white dwarf in their center, often visible in optical/UV images.
- SNR may contain a neutron star or pulsar (or a black hole) that is usually faint against the bright, shock-heated shell. Astronomy Stack Exchange
- Emission Mechanism
- PN glow primarily by photo-ionization (UV light from the white dwarf excites the shellāstrong O III, H α lines).
- SNR shine by shock-heating and synchrotron emission (high [S II]/H α ratios; strong radio and X-ray signatures). Astronomy Notes
2. What Governs a Starās Supernova Type & How āSizeā Is Determined
- Progenitor Mass (āSizeā)
- Core-collapse (Types II, Ib/c): Stars with initial masses ā³ 8 Mā end their lives in a supernova once fusion can no longer support the iron core.
- Type Ia: A 1.4 Mā white dwarf in a binary accretes mass until runaway carbon fusion detonates it.
- Measuring Stellar āSizeā via Parallax
- Parallax ā Distance: Missions like Hipparcos/Gaia measure a starās annual parallax angle to determine its distance, ddd.
- Brightness + Distance ā Luminosity: Observed flux FFF yields absolute luminosity L=4Ļd2FL=4\pi d^2FL=4Ļd2F.
- Luminosity + Temperature ā Radius: Using the StefanāBoltzmann law,
L=4ĻR2ĻTeff4ā¹R=L4ĻĻTeff4ā. L = 4\pi R^2\sigma T_{\rm eff}^4 \quad\Longrightarrow\quad R = \sqrt{\frac{L}{4\pi\sigma T_{\rm eff}^4}}\,.L=4ĻR2ĻTeff4ā¹R=4ĻĻTeff4L.
Thus, āsizeā (radius) depends on distance from parallax, measured brightness, and spectroscopic temperature.
So yesā
a starās mass (and thus āsizeā) determines which kind of supernova it can undergo, and we infer that size through parallax-based distance measurements combined with photometry and spectroscopy.
Sources
o4-mini
You said:
why do supernovae remnants surround the core remnant if the shockwave should carry it all away pretty darn quick?
ChatGPT said:
Thought for 13 seconds
Because the explosionās blast starts
from the collapsing core itself and pushes the
starās envelope outward, the expelled material naturally
expands as a shell centered on the new compact remnant. Hereās why that shell remains visible around the core:
- Shock Launches Inside Out
- The core collapse and bounce create a shock right at the boundary between the protoāneutron star and the overlying mantle. That shock plows outward, accelerating the envelope while the core stays put. Wikipedia
- Core Receives Only a Small āKickā
- Neutron stars often get a natal kick of a few hundred km/s, but the ejecta travels at thousands of km/s. The bulk of the mass is thrown off symmetrically, so it always expands in a roughly spherical shell around the (nearly stationary) remnant. A&A
- Deceleration by Interstellar Medium
- As the ejecta runs into surrounding gas, it slows and piles up into a thin, dense shellāwhat we observe as the supernova remnant (SNR). That shell continues to surround the central neutron star or black hole as it coasts outward. Wikipedia
- Reverse Shock
- A reverse shockāāāformed when the forward shock slows in the ISMāāāpropagates back inward, heating inner ejecta and further defining the hollow shell structure that keeps the remnantās āwallā around the core. HEASARC
So even though the material is driven away at high speed, it is always launched
around the core. From our vantage, we see that expanding shell still centered on the compact remnantājust like a balloon being inflated around a seed.