I can Prove that Neutron Decay doesn't Happen by a Quark Transforming.

talanum1

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Proof:
Take the reaction:

u+e^-→d+ν_e (1)

Since the process is called "electron capture" the electron can't have changed into the neutrino, which is therefore illegally produced. So the reaction can't happen like that. Now if we rewrite (1) as:

u+e^-+(ν_e)¯+ν_e→d+ν_e (2)

and we cancel the neutrino on both sides to get:

u+e^-+(ν_e)¯→d (3)

we see that the reaction couldn't have happened like this because the electron anti-neutrino illegally ceased to exist. Instead, we must find a way for the electron and electron anti-neutrino to combine into energy. The first step toward this is by assuming the electron and electron anti-neutrino bonded to form an anti-ud. So we have:

u+u¯d→d+u¯u (4)

we may do this because the anti-uu can decay into energy. This reaction could have happened. It is also consistent with the data and would look like the process of (1) since in addition the neutrino could also have been produced (see (2)) and the anti-uu annihilation energy could have been absorbed by the neutrino. We see now that the only thing that could have happened is that the u changed places with the d and that the quarks didn't transform (change flavor). QED.

Since no photons are emitted in process (4), (2) we must assume the neutron and neutrino absorb the energy set free.

We can use my formula to cause proton decay for energy production: just supply electrons and pi-minus mass-energy to hydrogen. The susequent binding to form Deuterium would add to the energy released. The energy required is pi-minus mass = 139.6 MeV/c^2.

An alternative view of neutron decay is thus needed. I postulate that it happens as follows:

1. An u-anti-u is created from energy near the neutron.
2. The u quark changes places with a d quark in the neutron leaving a proton and anti-ud.
3. The anti-ud decays to an electron and electron anti-neutrino via a virtual W-minus.

This happens via the formulas:

n→p+e^-+ν¯_e

or:

udd+u¯u →uud+u¯d →uud+e^-+ν¯_e.

This is also consistent with the data.

I can even write the in-between state. It is:

ud-d-u¯-u

and then a virtual particle-complex of the same flavors tries out the possible rearrangement:

ud-u-u¯-d

and finding the energy less it transports the quarks into the new state and unbinds. If the other side is to write down the in-between state it must be: “d/u-virtual-W-minus” which is undefined and absurd. I mean by "d/u" a particle that is both a down and up quark at the same time: absurd. This follows from the usual picture and considering time as discrete. Then there is a circle around the vertex where time is equal inside of, and both d and u is in the circle, so the statement follows.
The proof above suggests that if electrons and electron antineutrinos and protons are available then the protons will decay just to neutrons.
We therefore state that all particle transformations can be written as:

qqq+qq¯ →qqq+qq¯

or as:

qq¯+qq¯→qq¯+qq¯

where they can be expanded if the qq¯ decays to electron/positron + electron antineutrino/electron neutrino. Actually also:

qqq+qq¯ →qqq+qq¯ + npp¯

where n is a small natural number and p is some particle(s).

We incedentally state that all Feynmann diagrams are unphysical because they contain nodes where we need 1/∞ in both time and space and since ∞ is unphysical the statement follows.

Another reason for believing my equation is because the conventional physicist cannot give a mechanism for neutron decay. Saying that the d emitting a W- is the mechanism does not tell me where the W- comes from. My way the mechanism is simple contact forces (like two billiard balls colliding) of one quark on another.
The test for this is that neutron decay would happen profusely at the supplied creation energy of a uu¯ ( mass (uu¯) = mass (pi-zero)/2 = 135/2 = 67.5 MeV/c^2) and not only at W-minus creation energy (80 GeV/c^2).

Conflict of Interest: The author reports no conflict of interest.

Data Access: no data access is required.

Ethics: no animals or humans were used in the research.

Bibliography:

[1] L Strauss. Inleidende Fisika. Van Schaik 1987.
[2] Electron Capture. Wikipedia. Internet. 2025

Funding: No funding was received for this research.
 
Proof:
Take the reaction:

u+e^-→d+ν_e (1)

Since the process is called "electron capture" the electron can't have changed into the neutrino, which is therefore illegally produced. So the reaction can't happen like that. Now if we rewrite (1) as:

u+e^-+(ν_e)¯+ν_e→d+ν_e (2)

and we cancel the neutrino on both sides to get:

u+e^-+(ν_e)¯→d (3)

we see that the reaction couldn't have happened like this because the electron anti-neutrino illegally ceased to exist. Instead, we must find a way for the electron and electron anti-neutrino to combine into energy. The first step toward this is by assuming the electron and electron anti-neutrino bonded to form an anti-ud. So we have:

u+u¯d→d+u¯u (4)

we may do this because the anti-uu can decay into energy. This reaction could have happened. It is also consistent with the data and would look like the process of (1) since in addition the neutrino could also have been produced (see (2)) and the anti-uu annihilation energy could have been absorbed by the neutrino. We see now that the only thing that could have happened is that the u changed places with the d and that the quarks didn't transform (change flavor). QED.

Since no photons are emitted in process (4), (2) we must assume the neutron and neutrino absorb the energy set free.

We can use my formula to cause proton decay for energy production: just supply electrons and pi-minus mass-energy to hydrogen. The susequent binding to form Deuterium would add to the energy released. The energy required is pi-minus mass = 139.6 MeV/c^2.

An alternative view of neutron decay is thus needed. I postulate that it happens as follows:

1. An u-anti-u is created from energy near the neutron.
2. The u quark changes places with a d quark in the neutron leaving a proton and anti-ud.
3. The anti-ud decays to an electron and electron anti-neutrino via a virtual W-minus.

This happens via the formulas:

n→p+e^-+ν¯_e

or:

udd+u¯u →uud+u¯d →uud+e^-+ν¯_e.

This is also consistent with the data.

I can even write the in-between state. It is:

ud-d-u¯-u

and then a virtual particle-complex of the same flavors tries out the possible rearrangement:

ud-u-u¯-d

and finding the energy less it transports the quarks into the new state and unbinds. If the other side is to write down the in-between state it must be: “d/u-virtual-W-minus” which is undefined and absurd. I mean by "d/u" a particle that is both a down and up quark at the same time: absurd. This follows from the usual picture and considering time as discrete. Then there is a circle around the vertex where time is equal inside of, and both d and u is in the circle, so the statement follows.
The proof above suggests that if electrons and electron antineutrinos and protons are available then the protons will decay just to neutrons.
We therefore state that all particle transformations can be written as:

qqq+qq¯ →qqq+qq¯

or as:

qq¯+qq¯→qq¯+qq¯

where they can be expanded if the qq¯ decays to electron/positron + electron antineutrino/electron neutrino. Actually also:

qqq+qq¯ →qqq+qq¯ + npp¯

where n is a small natural number and p is some particle(s).

We incedentally state that all Feynmann diagrams are unphysical because they contain nodes where we need 1/∞ in both time and space and since ∞ is unphysical the statement follows.

Another reason for believing my equation is because the conventional physicist cannot give a mechanism for neutron decay. Saying that the d emitting a W- is the mechanism does not tell me where the W- comes from. My way the mechanism is simple contact forces (like two billiard balls colliding) of one quark on another.
The test for this is that neutron decay would happen profusely at the supplied creation energy of a uu¯ ( mass (uu¯) = mass (pi-zero)/2 = 135/2 = 67.5 MeV/c^2) and not only at W-minus creation energy (80 GeV/c^2).

Conflict of Interest: The author reports no conflict of interest.

Data Access: no data access is required.

Ethics: no animals or humans were used in the research.

Bibliography:

[1] L Strauss. Inleidende Fisika. Van Schaik 1987.
[2] Electron Capture. Wikipedia. Internet. 2025

Funding: No funding was received for this research.
I know it would require effort on your part, but you need to indicate the math notation/symbols where possible.

When I self taught myself logical math simply to revert back to the basics while I was teaching myself linear algebra and calculus, it was very enjoyable to me and the symbols played a key role as everything became clearer to me (¬, ~ ∧, &, :, and, ·, ∨ etc) I'd say almost G-d-like in that I realized that the entire world really is just math. Math is so divine in its complexity but ultimately logic that for me it feels as if I am brought closer to G-d. Only he could provide us the intellect to figure it out.

Anyways, I digress. Math notations allow me to more easily follow the physics you present. Just a note if you have the time in the future. Maybe you're not interested in appealing to the layperson lol I don't know. If you are, that helps :)
 
Your biggest problem is explaining electron-u-quark combination to produce d quark and neutrino. I can explain it (see text).

(4) is more beautiful than (1).
 
Maybe I should clarify why "neutrino is illegally produced": since the process is called "electron capture" the electron can't have turned into the neutrino, therefore the neutrino must have been produced from energy. Since the antimatter equivalent of the neutrino has not also been produced, the neutrino has been illegally produced.
 
... the neutrino has been illegally produced.

That's not the law here in the United States ... "electron capture" is protected under the 1st Amendment of our Constitution ... we can produce any and all neutrinos anytime we want ... it's our God-given right as AMERICANS ...

Neutrinos don't come with return addresses ... how are you individualizing this crime? ... oh wait, that's only important here in the USA, nevermind ... and what's the punishment, making people collect up all the neutrinos they've produced this way ... good luck with that ... should keep the folks at CERN busy for awhile ...

Ha ha ... just joking ... scientific laws are assumptions ... if there's an illegal neutrino floating about, I'd first suspect your assumptions ... starting with anti-matter and matter being produced in equal amounts ...

ETA: I agree with S'Cananaian ... you have to define your variables in your equations ... and these definitions need to be understandable to your audience ... here on USMB, that means high school graduates ... folks who don't know what a vector is let alone a field tensor ...

Seriously ... can't even get a thesis mill to publish this? ... what laws are you following? ...
 
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shockedcanadian: you can ask an AI for what the notation means.
 
I'll write out what the symbols mean, but it's going to take time.
 
u = up quark
e^- = electron
d = down quark
v_e = electron neutrino
-> = goes to
(v_e)^- = electron anti-neutrino
u^-d = anti-up down meson
u^-u = anti-up up meson
p = proton
uud = proton
udd = neutron
 
u = up quark
e^- = electron
d = down quark
v_e = electron neutrino
-> = goes to
(v_e)^- = electron anti-neutrino
u^-d = anti-up down meson
u^-u = anti-up up meson
p = proton
uud = proton
udd = neutron

Your equation #1 appears to be wrong then ... that's not beta decay ...

u + e^- --> d + v_e + e^-

The neutrino comes from the W boson, the electron is radiated away as beta radiation ... and I believe that's a different electron, the first having been "captured" by the up quark ...

Once you're older enough to attend high school, they'll teach you something called "conservation laws" ... on one side of your equation, we have ≈ 0.5 MeV mass for the electron, the other side has 10^-9 eV mass for the quark ... that violates the Law of Conservation of Mass ...

You're whole theory is based on creating and destroying mass willy-nilly ... whatever suits your purpose ... that's not how science works, son ...

Try again ... this time start with real equations ... not these made-up imaginary magical ones ...
 
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That equation does not conserve charge:

2/3 - 1 = -1/3 ~= -1/3 - 1 = -4/3

velocity can change into mass: m' = gamma*m_0.
 
"So there's no such thing as beta radiation? ...

What are m' and gamma*m_0? ..."

There is beta radiation in for example neutron decay, but not in electron capture.

m' = relativistic mass
gamma = 1/sqrt(1-v^2/c^2)
m_0 = rest mass/
 
My formula has definite in-between sates for all instances of the transition. Theirs has not.
 

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