Follow along with the video below to see how to install our site as a web app on your home screen.
Note: This feature may not be available in some browsers.
A d has charge -1/3 and an anti-u has charge -2/3 giving -1 total.No ... it takes three quarks to carry a -1 charge ... isn't Conservation of Charge a thing in your universe? ...
I'm curious where you're getting your antiquarks ... there's no listing for them at Amazon ... you do know they've been missing these past few years ...
A d has charge -1/3 and an anti-u has charge -2/3 giving -1 total.
A d and anti-u do not annihilate one another: they've got different flavor.Where are you getting these? ... how are you keeping them apart until your annihilation reaction? ...
Maybe a link to a Feynmen diagram? ...
A d and anti-u do not annihilate one another: they've got different flavor.
Feynman. I'll look for it.
I get them from quark-antiquark production at the edge of a black hole.Then they'd form mesons ... and photons ... but where are you getting the antiquarks is what I'm asking ... they've been missing and I think you owe the scientific community an explanation ...
I get them from quark-antiquark production at the edge of a black hole.
I have posted a link to the Feynman diagram, see post #5.
... the diagram is misleading.
My workout of decay processes suggests the answer is "yes". It seems plausible given that flavor quantum number is not conserved by the weak interaction.So the answer to your question is "no" ... everyone else is wrong ... if you math is right, somebody should publish ...
My workout of decay processes suggests the answer is "yes". It seems plausible given that flavor quantum number is not conserved by the weak interaction.
It's not math, its Logic. Anyway the answer is almost "yes" since a s-anti-c, d-anti-c, d-anti-u, s-anti-u, b-anti-u all decays to a mu- and mu antineutrino. q-anti-t just don't decay equivalently because the anti-t decays too quickly. I don't know how this happens because I think it can't decay on its own.What does the math say? ... perhaps the confusion is with how you're isolating these quarks ... apart from working in contact with a black hole ... that's a little unrealistic ...
Looks like runaway imagination ... I had to ask for the reaction equation, and now you're disputing that, that's how lame this thread is ... your math is wrong, you must be a liberal ...
It's not math, its Logic. Anyway the answer is almost "yes" since a s-anti-c, d-anti-c, d-anti-u, s-anti-u, b-anti-u all decays to a mu- and mu antineutrino. q-anti-t just don't decay equivalently because the anti-t decays too quickly. I don't know how this happens because I think it can't decay on its own.