How do you....

[California Girl]

weigh your own head?

Without using medical equipment.

 

[Ernie S.]

weigh your own head?

Without using medical equipment.

You can only do it once and it requires an ax and a friend. It hurts less if you weigh your friend's head.

Trust me. I'm an engineer and we get paid to know these things.

 

[California Girl]

weigh your own head?

Without using medical equipment.

You can only do it once and it requires an ax and a friend. It hurts less if you weigh your friend's head.

Trust me. I'm an engineer and we get paid to know these things.

No, there is another way... that does not include death.

 

[Ernie S.]

Oh... Yours is likely a lot heavier than TM's as it contains a brain.

 

[dilloduck]

Which head ?

 

[RadiomanATL]

Water displacement is the only way I can think of.

 

[JBeukema]

What about lying on your side/back with your head on a scale?

 

[JBeukema]

Water displacement is the only way I can think of.

What if the density of all tissues is not known

 

[Ernie S.]

It could be done with a plank, placing a fulcrum under your neck. An assistant places weights on the plank until you balance. If your total weight is known, the weight of your head can be calculated.

 

[RadiomanATL]

Water displacement is the only way I can think of.

What if the density of all tissues is not known

You'd have to assume that the density of the head is, on average, the same as the density of the rest of the body.

 

[California Girl]

Water displacement is the only way I can think of.

^^^^^ That.

If you fill a bucket with water (or, in Radio's case, beer) and weigh it, then stick your head in it, and weigh it again... that gives you the weight of your head. I did not know that till today.

 

[Ernie S.]

Water displacement is the only way I can think of.

Water displacement would depend on density. A hollow headed Liberal's head being devoid of gray matter would be less dense.

 

[JBeukema]

Water displacement is the only way I can think of.

What if the density of all tissues is not known

You'd have to assume that the density of the head is, on average, the same as the density of the rest of the body.

I'm not sure whether that's an accurate assumption.
Also, some bodies are more adipose than others.

 

[JBeukema]

Water displacement is the only way I can think of.

^^^^^ That.

If you fill a bucket with water (or, in Radio's case, beer) and weigh it, then stick your head in it, and weigh it again... that gives you the weight of your head. I did not know that till today.

I have a rock and a balloon that displace the same amount of water...

 

[RadiomanATL]

Water displacement is the only way I can think of.

^^^^^ That.

If you fill a bucket with water (or, in Radio's case, beer) and weigh it, then stick your head in it, and weigh it again... that gives you the weight of your head. I did not know that till today.

Actually, I was thinking of filling a tub to the tip-top, getting in and totally immersing yourself. Measure the water that spills out. Then do it again, and this time leave your head above water. Measure the spillage again. Use your weight to calculate the volume to weight ratio, and then the difference in spillage each times could give you your approximate head weight.

You would have to assume that your head is the same approximate density as the rest of your body though.

 

[RadiomanATL]

What if the density of all tissues is not known

You'd have to assume that the density of the head is, on average, the same as the density of the rest of the body.

I'm not sure whether that's an accurate assumption.
Also, some bodies are more adipose than others.

It'd be close enough probably. For a truly accurate measurement, you have to go with the axe method.

 

[JBeukema]

You would have to assume that your head is the same approximate density as the rest of your body though.

I think my method would be more accurate- especially in the cases of lardasses whose excess adipose tissue causes disproportionate displacement compared to persons with greater muscle mass and lower body fat percentage

 

[California Girl]

Water displacement is the only way I can think of.

^^^^^ That.

If you fill a bucket with water (or, in Radio's case, beer) and weigh it, then stick your head in it, and weigh it again... that gives you the weight of your head. I did not know that till today.

Actually, I was thinking of filling a tub to the tip-top, getting in and totally immersing yourself. Measure the water that spills out. Then do it again, and this time leave your head above water. Measure the spillage again. Use your weight to calculate the volume to weight ratio, and then the difference in spillage each times could give you your approximate head weight.

You would have to assume that your head is the same approximate density as the rest of your body though.

Be expensive to fill a tub with beer.

 

[RadiomanATL]

You would have to assume that your head is the same approximate density as the rest of your body though.

I think my method would be more accurate- especially in the cases of lardasses whose excess adipose tissue causes disproportionate displacement compared to persons with greater muscle mass and lower body fat percentage

Well, try it both ways and let us know the difference.

 

[RadiomanATL]

^^^^^ That.

If you fill a bucket with water (or, in Radio's case, beer) and weigh it, then stick your head in it, and weigh it again... that gives you the weight of your head. I did not know that till today.

Actually, I was thinking of filling a tub to the tip-top, getting in and totally immersing yourself. Measure the water that spills out. Then do it again, and this time leave your head above water. Measure the spillage again. Use your weight to calculate the volume to weight ratio, and then the difference in spillage each times could give you your approximate head weight.

You would have to assume that your head is the same approximate density as the rest of your body though.

Be expensive to fill a tub with beer.

But oh-so-awesome.